The Alphanumeric Series is another important part of the Reasoning section in the RBI Grade B Phase 1 exam. This topic usually carries 3 to 5 marks. It is easy to score. But only if you have a strong foundation. It tests how attentive you are to details, how well you can recognize the patterns, and how logically you can think to come to conclusions. In these questions, you will have to find patterns in a mix of letters, numbers, and symbols. Therefore, it is super essential to master this topic to maximize your overall score. But all that is only possible if you practice well and become confident of your success. In this blog, we’ll reflect on the most effective, simple, and practical tips to solve these questions easily and accurately.
Many aspirants find this topic tough. Why? Because it has mixed elements and lookalike over confusing choices. But if you have the right strategy, you can solve them quickly and more accurately.
Here are some of the best tips to master the art of answering such questions:
You need to start by learning the pattern behind how letters, numbers, and symbols are arranged. To get a good understanding of the structure, you’ll have to train your mind to:
The more you practice, the faster you’ll recognize common patterns.
Many questions are based on alphabetical positions, or reverse orders. So, you need to:
Symbols are often used to distract or add complexity. So, if you want to master the use of symbols, you need to:
Mock tests will help you learn the application and timing. They will help you:
Directions (1-5): Answer the questions based on the information given below.
@ 3 G $ I 4 S 7 # U X 2 1 + A 8 H 6 $ 9 ^ M P ! # 5 %
Step I: If the number is immediately followed by a symbol then it will interchange with that symbol.
Step II: All even numbers given in the series are written in ascending order between 10th and 11th element from the left end of the series obtained after step I.
Step III: The symbols immediately preceded by a number and immediately succeeded by a letter are written in the same order between 11th element and 12th element from the right end of the series obtained after step II.
Step IV: The odd numbers immediately followed by a letter are written at the beginning of the series in the descending order.
Note: Step II is performed after completion of step I, similarly, step III is performed after the completion of step II and so on.
Question 1: In step II, which of the following element is between the 9th element and 11th element from the right end?
A) M
B) P
C) H
D) $
E) +
Solution:
Given series:
@ 3 G $ I 4 S 7 # U X 2 1 + A 8 H 6 $ 9 ^ M P ! # 5 %
Step I: If the number is followed by a symbol then it will interchange with that symbol.
So, after applying the condition given in step I, we get,
@ 3 G $ I 4 S # 7 U X 2 + 1 A 8 H $ 6 ^ 9 M P ! # % 5
Step II: All even numbers given in the series are written between 10th and 11th element from the left, and then arranged in ascending order.
After applying the condition given in step II, we get,
@ 3 G $ I S # 7 U 2 4 6 8 X + 1 A H $ ^ 9 M P ! # % 5
Step III: The symbols preceded by a number and succeeded by a letter is written between 11th element and 12th element from the right end.
There is no such symbol which is preceded by a number and succeeded by a letter so, the series remains the same as in step II.
@ 3 G $ I S # 7 U 2 4 6 8 X + 1 A H $ ^ 9 M P ! # % 5
Step IV: The odd numbers followed by a letter are written at the beginning of the series in the descending order.
After applying the condition given in step IV, we get,
9 7 3 1 @ G $ I S # U 2 4 6 8 X + A H $ ^ M P ! # % 5
“H” will be in between the 9th and 11th element from the right end in step II.
Hence, option c.
Question 2: How many elements are there to the right of “6” in step IV?
A) Five
B) Ten
C) Two
D) Thirteen
E) Eighteen
Solution:
Given series:
@ 3 G $ I 4 S 7 # U X 2 1 + A 8 H 6 $ 9 ^ M P ! # 5 %
Step I: If the number is followed by a symbol then it will interchange with that symbol.
So, after applying the condition given in step I, we get,
@ 3 G $ I 4 S # 7 U X 2 + 1 A 8 H $ 6 ^ 9 M P ! # % 5
Step II: All even numbers given in the series are written between 10th and 11th element from the left, and then arranged in ascending order.
After applying the condition given in step II, we get,
@ 3 G $ I S # 7 U 2 4 6 8 X + 1 A H $ ^ 9 M P ! # % 5
Step III: The symbols preceded by a number and succeeded by a letter is written between 11th element and 12th element from the right end.
There is no such symbol which is preceded by a number and succeeded by a letter so, the series remains the same as in step II.
@ 3 G $ I S # 7 U 2 4 6 8 X + 1 A H $ ^ 9 M P ! # % 5
Step IV: The odd numbers followed by a letter are written at the beginning of the series in the descending order.
After applying the condition given in step IV, we get,
9 7 3 1 @ G $ I S # U 2 4 6 8 X + A H $ ^ M P ! # % 5
There are 13 elements to the right of ‘6’ in step IV.
Hence, option d.
Question 3: How many symbols are there which are immediately followed by vowels in step I?
A) One
B) Two
C) Three
D) None
E) Five
Solution:
Given series:
@ 3 G $ I 4 S 7 # U X 2 1 + A 8 H 6 $ 9 ^ M P ! # 5 %
Step I: If the number is followed by a symbol then it will interchange with that symbol.
So, after applying the condition given in step I, we get,
@ 3 G $ I 4 S # 7 U X 2 + 1 A 8 H $ 6 ^ 9 M P ! # % 5
Step II: All even numbers given in the series are written between 10th and 11th element from the left, and then arranged in ascending order.
After applying the condition given in step II, we get,
@ 3 G $ I S # 7 U 2 4 6 8 X + 1 A H $ ^ 9 M P ! # % 5
Step III: The symbols preceded by a number and succeeded by a letter is written between 11th element and 12th element from the right end.
There is no such symbol which is preceded by a number and succeeded by a letter so, the series remains the same as in step II.
@ 3 G $ I S # 7 U 2 4 6 8 X + 1 A H $ ^ 9 M P ! # % 5
Step IV: The odd numbers followed by a letter are written at the beginning of the series in the descending order.
After applying the condition given in step IV, we get,
9 7 3 1 @ G $ I S # U 2 4 6 8 X + A H $ ^ M P ! # % 5
There is only one such symbol which is followed by vowel in step I.
Hence, option a.
Question 4: Which element is 4th to the right of the element which is 5th to the left of the element which is immediate right of P in step III?
A) M
B) +
C) 9
D) A
E) None of the above
Solution:
Given series:
@ 3 G $ I 4 S 7 # U X 2 1 + A 8 H 6 $ 9 ^ M P ! # 5 %
Step I: If the number is followed by a symbol then it will interchange with that symbol.
So, after applying the condition given in step I, we get,
@ 3 G $ I 4 S # 7 U X 2 + 1 A 8 H $ 6 ^ 9 M P ! # % 5
Step II: All even numbers given in the series are written between 10th and 11th element from the left, and then arranged in ascending order.
After applying the condition given in step II, we get,
@ 3 G $ I S # 7 U 2 4 6 8 X + 1 A H $ ^ 9 M P ! # % 5
Step III: The symbols preceded by a number and succeeded by a letter is written between 11th element and 12th element from the right end.
There is no such symbol which is preceded by a number and succeeded by a letter so, the series remains the same as in step II.
@ 3 G $ I S # 7 U 2 4 6 8 X + 1 A H $ ^ 9 M P ! # % 5
Step IV: The odd numbers followed by a letter are written at the beginning of the series in the descending order.
After applying the condition given in step IV, we get,
9 7 3 1 @ G $ I S # U 2 4 6 8 X + A H $ ^ M P ! # % 5
The element to the immediate right of P is ! and 5th to the ! is $ and 4th to the right of $ is P.
Hence, option e.
Question 5: In step IV, how many symbols are immediately preceded by symbols?
A) Two
B) One
C) Three
D) Five
E) None
Solution:
Given series:
@ 3 G $ I 4 S 7 # U X 2 1 + A 8 H 6 $ 9 ^ M P ! # 5 %
Step I: If the number is followed by a symbol then it will interchange with that symbol.
So, after applying the condition given in step I, we get,
@ 3 G $ I 4 S # 7 U X 2 + 1 A 8 H $ 6 ^ 9 M P ! # % 5
Step II: All even numbers given in the series are written between 10th and 11th element from the left, and then arranged in ascending order.
After applying the condition given in step II, we get,
@ 3 G $ I S # 7 U 2 4 6 8 X + 1 A H $ ^ 9 M P ! # % 5
Step III: The symbols preceded by a number and succeeded by a letter is written between 11th element and 12th element from the right end.
There is no such symbol which is preceded by a number and succeeded by a letter so, the series remains the same as in step II.
@ 3 G $ I S # 7 U 2 4 6 8 X + 1 A H $ ^ 9 M P ! # % 5
Step IV: The odd numbers followed by a letter are written at the beginning of the series in the descending order.
After applying the condition given in step IV, we get,
9 7 3 1 @ G $ I S # U 2 4 6 8 X + A H $ ^ M P ! # % 5
There are three such symbols which are preceded by symbols.
Hence, option c.
Practice is the door to success in Alphanumeric Series questions in the RBI Grade B exam. Start with understanding patterns, apply logic smartly, and practice regularly with RBI Grade B 2025 mock tests. Invest sufficient time in practicing different types of questions related to the topic and improve your speed and accuracy with every passing day. Stay fully focused and keep going!
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Around 3 to 5 questions in Phase 1.
Yes, if practiced well, it’s high scoring.
Yes, it helps spot patterns faster.
Sometimes yes, sometimes just to confuse.
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