Time, Speed & Distance For SSC CGL, Check All Details

Time, Speed & Distance For SSC CGL

Time, Speed & Distance For SSC CGL: This topic is easy, and the good part is that candidates are already familiar with this topic, they must have learned about it during their school days. Candidates can expect at least 1-2 questions in Time, Speed & Distance for SSC CGL exam and can expect the level of questions as moderate to difficult. In this blog, we have provided the basic concept of Time, Speed & Distance For SSC CGL, questions in Hindi and Language along with the solutions with explanations. In SSC CGL Exam the questions they will ask will be on the same concept but the type of questions may differ. So, candidates are advised to go through the questions very carefully and practice them.

Concept of Time, Speed & Distance

Time, Speed & Distance are the mathematical concepts that are used in calculating rates and distances. These concepts mainly cover the areas related to motion in a straight line, circular motion, clocks, boats and streams, etc.

Relationship Between Time, Speed & Distance (Formulas)

It is mandatory to know the relationship between Time, Speed & Distance.

1. Distance=Speed X Time
2. Speed=Distance/Time
3. Time=Distance/Speed

Units of Time, Speed & Distance

• Speed: kilometers per hour (km/h), meters per second (m/s), miles per hour (mph), feet per second (ft/s).
• Time: seconds (s), minutes (min), hours (h), days (d).
• Distance: kilometers (km), meters (m), miles (mi), feet (ft).

Important Questions of Time, Speed & Distance

In this section, we have provided some different types of questions that SSC can ask in the SSC CGL Exam. We have provided the questions by analyzing the previous year question papers.

Time, Speed & Distance Questions in the English Language

Question 1: A train takes 1 hour less to cover a certain distance if it travels with a speed of 25 m/s instead of 20 m/s. Find the certain distance.

A) 300 km

B) 320 km

C) 330 km

D) 360 km

Question 2: Speed of stream is 15 km/hr and speed of boat in still water is 20% more than speed of stream. Find the total time taken by the boat to cover a distance of 10.5 km in upstream and 16.5 km in downstream.

A) 3 hours

B) 5 hours

C) 4 hours

D) 6 hours

Question 3: A train takes 53 seconds to cross a 448 metre long platform. If the speed of the train is 72 km/h, then find the length of the train.

A) 612 metres

B) 606 metres

C) 556 metres

D) 580 metres

Question 4: Train ‘A’ of length 430 metres crosses a platform of length 410 metres, in 40 seconds. The ratio of the speed of train ‘A’ and train ‘B’ is 3:2, respectively. If train ‘B’ can cross a pole in 25 seconds, then find the length of the train.

A) 420 metres

B) 350 metres

C) 300 metres

D) 320 metres

Question 5: Speed of a boat in still water is 20 km/h. The boat takes 1 hour more to cover 60 km in upstream than the time taken by it to cover 75 km in downstream. Find the speed of the current.

A) 7 km/h

B) 4.5 km/h

C) 2.5 km/h

D) 5 km/h

Question 6: Ratio of downstream speed to upstream speed of a boat is 8:7. Time taken by boat to cover 360 km downstream and 420 km upstream is 21 hours then find the time taken by boat to cover 675 km in still water.

A) 22 hours

B) 15 hours

C) 20 hours

D) 18 hours

Question 7: A boat can travel 64 km in upstream and same distance in downstream in a total of 10 hours. The ratio of speed of the boat in still water to the speed of the stream is 5:3. Find the speed of the boat in still water.

A) 20 km/h

B) 12 km/h

C) 15 km/h

D) 30 km/h

Question 8: A train takes 21 seconds to cross a tree and 30 seconds to cross a 75-metre-long trailer truck moving at the speed of 18 km/h in the same direction as that of train. Find the length of the train.

A) 540 metres

B) 475 metres

C) 525 metres

D) 425 metres

Question 9: The time taken by a train of length 200 metres to cross a pole is 8 seconds. Find the time taken by the train to cross a platform which is 325 metres long?

A) 24 seconds

B) 25 seconds

C) 20 seconds

D) 21 seconds

Question 10: A train takes 15 seconds to cross a pole. Find the time taken by the same train to cross a 300-metre long platform given that the length of train is 100 metres less than that of the platform.

A) 48 seconds

B) 37.5 seconds

C) 75 seconds

D) 25 seconds

Time, Speed & Distance Questions in the Hindi Language

प्रश्न 1: एक ट्रेन एक निश्चित दूरी तय करने में 1 hour कम समय लेती है यदि वह 20 m/s के बजाय 25 m/s की गति से यात्रा करती है। निश्चित दूरी ज्ञात करें।

A) 300 km

B) 320 km

C) 330 km

D) 360 km

प्रश्न 2: धारा की गति 15 km/hr है और शांत जल में नाव की गति धारा की गति से 20% अधिक है। नाव द्वारा धारा के विरुद्ध 10.5 km और धारा के अनुप्रवाह 16.5 km की दूरी तय करने में लिया गया कुल समय ज्ञात करें।

A) 3 hours

B) 5 hours

C) 4 hours

D) 6 hours

प्रश्न 3: एक ट्रेन 448 metre लंबे प्लेटफॉर्म को पार करने में 53 seconds का समय लेती है। यदि ट्रेन की गति 72 km/h है, तो ट्रेन की लंबाई ज्ञात करें।

A) 612 metres

B) 606 metres

C) 556 metres

D) 580 metres

प्रश्न 4: 430 मीटर लम्बी ट्रेन ‘A’ 410 मीटर लम्बे प्लेटफार्म को 40 सेकंड में पार करती है। ट्रेन ‘A’ और ट्रेन ‘B’ की गति का अनुपात क्रमशः 3:2 है। यदि ट्रेन ‘B’ एक खंभे को 25 सेकंड में पार कर सकती है, तो ट्रेन की लंबाई ज्ञात कीजिए।

A) 420 मीटर

B) 350 मीटर

C) 300 मीटर

D) 320 मीटर

प्रश्न 5: शांत जल में एक नाव की गति 20 km/h है। नाव द्वारा धारा विरुद्ध में 60 km की दूरी तय करने में लिया गया समय नाव द्वारा धारा अनुप्रवाह में 75 km की दूरी तय करने में लिए गए समय से 1 hour अधिक है। धारा की गति ज्ञात करें।

A) 7 km/h

B) 4.5 km/h

C) 2.5 km/h

D) 5 km/h

प्रश्न 6: एक नाव की धारा अनुप्रवाह गति और धारा विरुद्ध गति का अनुपात 8:7 है। नाव द्वारा धारा अनुप्रवाह में 360km और धारा विरुद्ध में 420km की दूरी तय करने में 21 hours का समय लगता है तो नाव द्वारा शांत जल में 675km की दूरी तय करने में लिया गया समय ज्ञात कीजिए।

A) 22 hours

B) 15 hours

C) 20 hours

D) 18 hours

प्रश्न 7: एक नाव धारा विरुद्ध में 64 km और धारा अनुप्रवाह में समान दूरी कुल 10 hours में तय कर सकती है। शांत जल में नाव की गति और धारा की गति का अनुपात 5:3 है। शांत जल में नाव की गति ज्ञात करें।

A) 20 km/h

B) 12 km/h

C) 15 km/h

D) 30 km/h

प्रश्न 8: एक ट्रेन एक पेड़ को पार करने में 21 seconds और ट्रेन के समान दिशा में 18 km/h की गति से चल रहे 75 metre लंबे ट्रेलर ट्रक को पार करने में 30 seconds का समय लेती है। ट्रेन की लंबाई ज्ञात करें।

A) 540 metres

B) 475 metres

C) 525 metres

D) 425 metres

प्रश्न 9: 200m लम्बी एक ट्रेन को एक खंभे को पार करने में 8 सेकंड का समय लगता है। 325 मीटर लम्बे प्लेटफार्म को पार करने में ट्रेन को कितना समय लगेगा?

A) 24 सेकेंड

B) 25 सेकेंड

C) 20 सेकेंड

D) 21 सेकेंड

प्रश्न 10: एक ट्रेन एक खम्भे को पार करने में 15seconds का समय लेती है। उसी ट्रेन द्वारा 300 meters लंबे प्लेटफॉर्म को पार करने में लिया गया समय ज्ञात कीजिए, यह देखते हुए कि ट्रेन की लंबाई प्लेटफॉर्म की तुलना में 100 meters कम है।

A) 48 seconds

B) 37.5 seconds

C) 75 seconds

D) 25 seconds

ANSWER KEYS and SOLUTIONS:

Time, Speed & Distance Solutions of Above Questions with Explanation

Solution 1: 4)

Let the required distance be ‘x’ metres.

ATQ;

(x/20) – (x/25) = 3600

Or, {(5x – 4x)/100} = 3600

Or, x = 360000 metres = 360 km.

Hence, option d.

Solution 2: 3)

Speed of boat in still water = (1.20 X 15) = 18 km/hr

Upstream speed of the boat = 18 – 15 = 3 km/hr

Downstream speed of the boat = 18 + 15 = 33 km/h

Required time = (10.5/3) + (16.5/33) = 3.5 + 0.5 = 4 hours

Hence, option c.

Solution 3: 1)

Let the length of the train be ‘L’ metres

Speed of the train = {72 X (5/18)} = 20 m/s

ATQ,

53 = {(448 + L)/20}

Or, 1060 = 448 + L

So, L = 612

Therefore, length of the train = 612 metres

Hence, option a.

Solution 4: 2)

Let speed of train ‘A’ and train ‘B’ be ‘3x’ m/s and ‘2x’ m/s, respectively.

ATQ,

3x = {(430 + 410)/40}

Or, x = 7

Now, speed of train ‘B’ = 2x = (2 X 7) = 14 m/s

So, length of train ‘B’ = (14 X 25) = 350 metres

Hence, option b.

Solution 5: 4)

Let the speed of the stream be ‘y’ km/h.

ATQ;

{60/(20 – y)} = 1 + {75/(20 + y)}

Or, 60 X (20 + y) = (20 – y) {(20 + y) + 75}

Or, 1200 + 60y = 400 – y² + 1500 – 75y

Or, y² + 135y – 700 = 0

Or, y² + 140y – 5y – 700 = 0

Or, y(y + 20) – 5(y + 20) = 0

Or, (y + 20)(y – 5) = 0

So, y = 5 or y = -20

Since, speed cannot be negative. So, y = 5

So, speed of the stream = 5 km/h

Hence, option d.

Solution 6: 4)

Let, speed of boat in downstream and upstream be ‘8x’ km/h and ‘7x’ km/h, respectively.

Speed of boat in still water = (8x + 7x)/2 = 7.5x km/h

So, (360/8x) + (420/7x) = 21

Or, (45/x) + (60/x) = 21

Or, 21x = 105

Or, x = 5

Required time taken = (675/7.5x) = 18 hours

Hence, option d.

Solution 7: 1)

Let the speed of the boat in still water and the speed of the stream be 5x km/hr and 3x km/hr, respectively

According to the question,

{64/(5x + 3x)} + {64/(5x – 3x)} = 10

Or, (64/8x) + (64/2x) = 10

Or, (8/x) + (32/x) = 10

Or, (8 + 32) = 10x

Or, 10x = 40

Or, x = 4

Speed of the boat in still water = 5x = 5 X 4 = 20 km/h

Hence, option a.

Solution 8: 3)

Let the length of the train = ‘d’ metres

Then, speed of the train = (d/21) m/s

Speed of the truck = 18 ÷ 3.6 = 5 m/s

And so, relative speed of the train with respect to the truck = (d/21) – 5 = {(d – 105)/21} m/s

And so, (d + 75) ÷ {(d – 105)/21} = 30

Or, 21d + 1575 = 30d – 3150

Or, 9d = 4725

And so, d = 4725 ÷ 9 = 525

Or, length of the train = 525 metres

Hence, option c.

Solution 9: 4)

Speed of train = (200/8) = 25 m/s

The time taken by the train to cross the platform = {(200 + 325)/25} = 21 seconds

Hence, option d.

Solution 10: 2)

Length of the train = 300 – 100 = 200 metres

So, speed of the train = (200/15) = (40/3) m/s

So, time taken to cross the platform = {(300 + 200) X 3} ÷ 40 = 37.5 seconds

Hence, option b.

Time, Speed & Distance For SSC CGL FAQs

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