Time Speed And Distance For IBPS RRB 2024 Exam

Time, Speed, and Distance (TSD) is one of the most important. Time, speed and distance are part of the quantitative section and are interrelated concepts that are often used to solve problems involving motion. This article aims to provide a brief knowledge of the Time Speed and Distance (TSD) concept for the IBPS RRB 2024 exam, formulas, and practical questions.

Time Speed and Distance Formulas

Distance=

From this, we can derive the other two formulas: Time and Speed 

Practical Questions For Time Speed and Distance

Question 1: A boat is travelling upstream at a resultant speed of 5 km/hr when it starts from B to A and then returns back to B in downstream. If the time taken while travelling upstream and downstream is in the ratio of 5:3 then find the speed of stream?

A) 1.67 km/hr

B) 2.34 km/hr

C) 3.34 km/hr

D) 6.67 km/hr

Question 2: The total time taken by a boat to cover 120 km while travelling upstream and 280 km while travelling downstream is (26/3) hours. The ratio of speed the boat in still water and the speed of the stream is 3:1. What was the downstream speed of the boat?

A) 60 km/hr

B) 30 km/hr

C) 51 km/hr

D) 45 km/hr

E) None of the above

Question 3: Train A starts from Delhi to Patna at 8:15 AM at an average speed of 15 m/s. Train B starts from Patna to Delhi at 10:35 AM at an average speed of 17.5 m/s. At what time the two trains will meet each other, if the distance between Delhi and Patna is 555 Km?

A) 2:05 PM

B) 2:15 PM

C) 2:25 PM

D) 2:30 PM

E) None of these

Question 4: Speed of the boat in still water is 200% more than the speed of stream. It can cover 110 Km downstream and 65 Km upstream in 12 hours. Find the time taken by the boat to cover 90 Km in downstream.

A) 5 hours 30 minutes

B) 5 hours

C) 4 hours

D) 4 hours 30 minutes

E) None of these

Question 5: A boat while travelling upstream can cover a distance of 240 km in 8 hours. If the speed of the boat is 40 km/hr, then how many hours would it take to cover 120 km while travelling downstream?

A) 2.25 hours

B) 2.4 hours

C) 3 hours

D) 3.2 hours

E) None of these

Question 6: A boat covers a distance of 288 km downstream and then comes back in 40 hours. If the ratio of downstream speed of boat to the upstream speed of boat is 3:2, respectively, then find the time taken by boat to travel a distance of 288 km upstream with the speed of stream double than the normal speed.

A) 40 hours

B) 38 hours

C) 32 hours

D) 36 hours

E) None of these

Question 7: A train of length 320 m can cross a boy standing on the platform and platform itself in 20 sec and 30 sec respectively. If the length of the platform is (x + 40) m, then find the value of 55% of x.

A) 45

B) 58

C) 66

D) 75

E) 85

Question 8: The ratio of speed of Sunny and Bobby is 4:3, respectively. Abhay can travel a distance of 720 km in 12 hours. If the speed of Bobby is 20% less than the speed of Abhay, then find the time taken by Sunny to travel a distance of 464 km.

A) 7.25 hours

B) 8 hours

C) 9.5 hours

D) 12 hours

E) 6 hours

Question 9: The total time taken by the boat to travel a distance of (x + 40) km upstream and (x – 40) km downstream with boat speed of 18 km/hr in still water is 32 hours. If the speed of stream is 2 km/hr, then find the time taken by boat to travel (x + 60) km upstream with stream speed 50% less than the normal stream speed.

A) 15 hours

B) 12 hours

C) 16 hours

D) 20 hours

E) 24 hours

Question 10: A dog starts chasing a train of length 2(x + 20) m which is running at 6 m/s. The dog reaches up to middle of the train, then turns back and starts running till he reaches the back end of the train. In this process, the dog travels a distance of 648 m with speed of 9 m/s. Find the length of train.

A) 180 m

B) 240 m

C) 270 m

D) 360 m

E) 540 m

Solution 1: A)

Solution 2: A)

Let the speed of the boat and speed of the stream be ‘3x’ km/hr and ‘x’ km/hr respectively.

According to the question,

[120 / (3x – x)] + [280 / (3x + x)] = 26/3

[120 / 2x] + [280 / 4x] = 26/3

[520 / 4x] = 26/3

So, x = 15

So, downstream speed of the boat = 3x + x = 4x = 60 km/hr

Hence, option a.

Solution 3: B)

Speed of train A = 15 × 18/5 = 54 Km/h

Speed of train B = 1.75 × 18/5 = 63 Km/h

Distance covered by train A in 2 hours 20 minutes = 54 × 7/3 = 126 Km

Relative speed of train A and train B together = 54 + 63 = 117 Km/h

Remaining distance = 555 – 126 = 429 Km

Time taken to cover 429 Km = 429 ÷ 117 = 11/3 hours = 3 hours 40 minutes

So, the two trains will meet each other at 10:35 + 3:40 = 13:75 = 14:15 = 2:15 PM

Hence, option b.

Solution 4: D)

Let, the speed of stream = ‘x’ Km/h

So, the speed of the boat in still water = x + 2x = ‘3x’ Km/h

So, according to question:

110/4x + 65/2x = 12

27.5/x + 32.5/x = 12

60/x = 12

x = 5

So, the downstream speed of the boat = 5 + 15 = 20 Km/h

So time taken to cover 90 Km downstream = 90 ÷ 20 = 4.5 hours = 4 hours 30 minutes

Hence, option d.

Solution 5: B)

Let the speed of the stream be x km/hr.

So, upstream speed = (40 – x) km/hr

According to the question,

240/(40 – x) = 8

x = 10 km/hr

So, downstream speed = 40 + x = 40 + 10 = 50 km/hr

Required time taken to cover the distance = 120/50 = 2.4 hours

Hence, option b.

Solution 6: C)

Let the downstream speed and upstream speed be ‘3x’ and ‘2x’ km/hr respectively.

According to question,

288/3x + 288/2x = 40

240x = 1440

x = 6

So, downstream speed = 3x = 18 km/hr

Upstream speed = 2x = 12 km/hr

Speed of stream = (18 – 12)/2 = 3 km/hr

And, speed of boat in still water = (18 + 12)/2 = 15 km/hr 

Therefore, required time = 288/ (15 – 3 × 2)

= 288/9 = 32 hours

Hence, option c.

Solution 7: C)

Let the speed of train be ‘s’ m/s.

According to question,

320/s = 20

s = 16 m/s

Also, {320 + (x + 40)}/16 = 30

320 + x + 40 = 480

x + 40 = 480 – 320

x = 120

Therefore, 55% of x = 0.55 × 120 = 66

Hence, option c.

Solution 8: A)

Speed of Abhay = 720 ÷ 12 = 60 km/hr

So, speed of Bobby = (100 – 20)% × 60 = 48 km/hr

Therefore, speed of Sunny = (4/3) × 48 = 64 km/hr

Therefore, required time = 464 ÷ 64 = 7.25 hours

Hence, option a.

Solution 9: D)

Downstream speed of boat = 18 + 2 = 20 km/hr

Upstream speed of boat = 18 – 2 = 16 km/hr

According to question,

(x + 40)/16 + (x – 40)/20 = 32

(5x + 200 + 4x – 160)/80 = 32

(9x + 40) = 2560

9x = 2520, x = 280

Therefore, required time = (280 + 60)/ (18 – 2 × 0.5)

= 340/17 = 20 hours

Hence, option d.

Solution 10: D)

Time taken by dog in the process = 648 ÷ 9 = 72 seconds

So, according to question,

(x + 20)/(9 – 6) + (x + 20)/(9 + 6) = 72

(x + 20)/3 + (x + 20)/15 = 72

[5(x + 20) + (x + 20)]/15 = 72

6(x + 20) = 1080

2(x + 20) = 360

Therefore, length of train = 360 m

Hence, option d.

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