Simplification For SSC CGL Exam: The SSC CGL Exam consists of four sections: General Intelligence & Reasoning, English Language & Comprehension, Quantitative Aptitude, and General Awareness. Simplification for SSC CGL Exam is one of the topics that belong to the Quantitative Aptitude section. Simplification is an easy topic that can be understood easily by the candidates. Candidates can expect at least 1-2 questions related to Simplification for SSC CGL Exam at an easy to moderate level. In this blog, we have provided the basic concept related to simplification. We have also provided the questions in Hindi and English language along with the solutions with explanations.
Simplification is used to solve the complex question by reducing and simplifying it to determine the solution. Using simplification can help to solve the bigger questions easily in fewer steps. It leads to solving the questions in less time. Certain rules can be implemented to solve the questions easily. One of those rules is the ‘BODMAS’ rule.
BODMAS: Bracket of Division Multiplication Addition Subtraction
According to the ‘BODMAS’ rule, for any simplification first we will solve bracket (B), after solving the bracket we will move on to of (O) which is multiplication, then divide (D), Multiply (M), Addition (A), and then last is Subtraction (S).
Example: 25-[7+{27-(18-6)}]
25-[7+{27-12}]
25-[7+15]
25-22
Solution: 3
Here, we have provided some questions related to the simplification of different types to help the candidates know the difficulty of the questions that can be asked by the SSC in the SSC CGL Exam. Candidates are advised to understand the concept first and then solve the questions.
Question 1: Find the simplified value of the given expression:
A) 16
B) 12
C) 20
D) 10
Question 2: Find the simplified value of the given expression.
182 ÷ 13 X 2 of 2.5 – 20 ÷ 5 X 2.5 – 17.7 + 2.7
A) 43
B) 42.4
C) 45
D) 46.2
Question 3: Find the simplified value of the given expression.
A) 11
B) 15
C) 22
D) 10
Question 4: Solve: {(25)2 + 24 ÷ 18 – 6 × 8 of 4 + (13 × 2) ÷ 4 + 88 – 47 ÷ 6 + 8}(1/2)
A) 23
B) 27
C) 17
D) 33
Question 5: Find the simplified value of the given expression:
A) 12/5
B) 27/5
C) 27/7
D) 12/7
Question 6: Find the simplified value of the given expression.
A) 180
B) 162
C) 154
D) 160
Question 7: Find the simplified value of the given expression.
75 ÷ 2.5 of 3 X 6 – 2.4 ÷ 0.6 X 10 + 2.6 – 1.4 + 2.8 – 2
A) 24
B) 20
C) 26
D) 22
Question 8: Find the simplified value of the given expression:
A) 71
B) 53
C) 128
D) 34
Question 9: Find the simplified value of the given expression:
A) 1
B) 2
C) 4
D) 5
Question 10: If √2 = 1.414, then find the value of
A) 2.01
B) 3.01
C) 4.01
D) 7.07
प्रश्न 1: दिए गए समीकरण का सरलीकृत मान ज्ञात कीजिए:
A) 16
B) 12
C) 20
D) 10
प्रश्न 2: दिए गए समीकरण का सरलीकृत मान ज्ञात कीजिए।
182 ÷ 13 X 2 of 2.5 – 20 ÷ 5 X 2.5 – 17.7 + 2.7
A) 43
B) 42.4
C) 45
D) 46.2
प्रश्न 3: दिए गए समीकरण का सरलीकृत मान ज्ञात कीजिए।
A) 11
B) 15
C) 22
D) 10
प्रश्न 4: हल करें: {(25)2 + 24 ÷ 18 – 6 × 8 of 4 + (13 × 2) ÷ 4 + 88 – 47 ÷ 6 + 8}(1/2)
A) 23
B) 27
C) 17
D) 33
प्रश्न 5: दिए गए समीकरण का सरलीकृत मान ज्ञात कीजिए:
A) 12/5
B) 27/5
C) 27/7
D) 12/7
प्रश्न 6: दिए गए समीकरण का सरलीकृत मान ज्ञात करें।
A) 180
B) 162
C) 154
D) 160
प्रश्न 7: दिए गए समीकरण का सरलीकृत मान ज्ञात कीजिए।
75 ÷ 2.5 of 3 X 6 – 2.4 ÷ 0.6 X 10 + 2.6 – 1.4 + 2.8 – 2
A) 24
B) 20
C) 26
D) 22
प्रश्न 8: दिए गए समीकरण का सरलीकृत मान ज्ञात कीजिए:
A) 71
B) 53
C) 128
D) 34
प्रश्न 9: दिए गए समीकरण का सरलीकृत मान ज्ञात करें:
A) 1
B) 2
C) 4
D) 5
प्रश्न 10: यदि √2 = 1.414 है तो
का मान ज्ञात कीजिए:
A) 2.01
B) 3.01
C) 4.01
D) 7.07
ANSWER KEYS and SOLUTIONS:
1) – 4) | 2) – 3) | 3) – 4) | 4) – 1) | 5) – 2) | 6) – 2) |
7) – 4) | 8) – 2) | 9) – 2) | 10) – 2) |
Solution 1: 4)
Hence, option d.
Solution 2: 3)
Given, 182 ÷ 13 X 2 of 2.5 – 20 ÷ 5 X 2.5 – 17.7 + 2.7
= 182 ÷ 13 X 5 – 20 ÷ 5 X 2.5 – 17.7 + 2.7
= 14 X 5 – 4 X 2.5 – 17.7 + 2.7
= 70 – 10 – 17.7 + 2.7
= 72.7 – 27.7
= 45
Hence, option c
Solution 3: 4)
Hence, option d
Solution 4: 1)
(25)2 + 24 ÷ 18 – 6 × 8 of 4 + (13 × 2) ÷ 4 + 88 – 47 ÷ 6 + 8 = 625 + (4/3) – 6 × 32 + (13/2) + 88 – (47/6) + 8
= 625 + (4/3) – 192 + (13/2) + 88 – (47/6) + 8 = 721 – 192 + (47/6) – (47/6) = 529
Desired answer = √529 = 23
Hence, option a.
Solution 5: 2)
Hence, option b.
Solution 6: 2)
Hence, option b
Solution 7: 4)
Applying BODMAS,
75 ÷ 2.5 of 3 X 6 – 2.4 ÷ 0.6 X 10 + 2.6 – 1.4 + 2.8 – 2
= 75 ÷ 7.5 X 6 – 2.4 ÷ 0.6 X 10 + 2.6 – 1.4 + 2.8 – 2
= 10 X 6 – 4 X 10 + 2.6 – 1.4 + 2.8 – 2
= 60 – 40 + 2.6 – 1.4 + 2.8 – 2
= 65.4 – 43.4
= 22
Hence, option d.
Solution 8: 2)
Hence, option b.
Solution 9: 2)
= 2
Hence, option b.
Solution 10: 2)
Given that,
Hence, option b.
We understand how important it is for students to have the right resources when preparing for the SSC GD exam. That’s why we are working on providing you with a comprehensive PDF focused on Simplification questions. This valuable resource will be available for download very soon. Stay tuned and keep an eye out, as we’ll be sharing the PDF shortly to help you strengthen your preparation and boost your confidence for the exam.
The difficulty level of questions of Simplification for SSC CGL Exam is Easy to Moderate.
The weightage of Simplification for SSC CGL Exam is 1-2 questions.
Simplification is used to solve the complex question by reducing and simplifying it to determine the solution.
Candidates can find the questions on simplification in this blog.
The ‘BODMAS’ rule is most implemented in Simplification.
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