Simplification For SSC CGL Exam, Check All Details

Simplification For SSC CGL Exam

Simplification For SSC CGL Exam: The SSC CGL Exam consists of four sections: General Intelligence & Reasoning, English Language & Comprehension, Quantitative Aptitude, and General Awareness. Simplification for SSC CGL Exam is one of the topics that belong to the Quantitative Aptitude section. Simplification is an easy topic that can be understood easily by the candidates. Candidates can expect at least 1-2 questions related to Simplification for SSC CGL Exam at an easy to moderate level. In this blog, we have provided the basic concept related to simplification. We have also provided the questions in Hindi and English language along with the solutions with explanations.

Basic Concept of Simplification

Simplification is used to solve the complex question by reducing and simplifying it to determine the solution. Using simplification can help to solve the bigger questions easily in fewer steps. It leads to solving the questions in less time. Certain rules can be implemented to solve the questions easily. One of those rules is the ‘BODMAS’ rule.

BODMAS: Bracket of Division Multiplication Addition Subtraction

According to the ‘BODMAS’ rule, for any simplification first we will solve bracket (B), after solving the bracket we will move on to of (O) which is multiplication, then divide (D), Multiply (M), Addition (A), and then last is Subtraction (S).

Example: 25-[7+{27-(18-6)}]

25-[7+{27-12}]

25-[7+15]

25-22

Solution: 3

Questions on Simplification with Solutions

Here, we have provided some questions related to the simplification of different types to help the candidates know the difficulty of the questions that can be asked by the SSC in the SSC CGL Exam. Candidates are advised to understand the concept first and then solve the questions.

Simplification Questions in the English Language

Question 1: Find the simplified value of the given expression:

A) 16

B) 12

C) 20

D) 10

Question 2: Find the simplified value of the given expression.

182 ÷ 13 X 2 of 2.5 – 20 ÷ 5 X 2.5 – 17.7 + 2.7

A) 43

B) 42.4

C) 45

D) 46.2

Question 3: Find the simplified value of the given expression.

A) 11

B) 15

C) 22

D) 10

Question 4: Solve: {(25)² + 24 ÷ 18 – 6 × 8 of 4 + (13 × 2) ÷ 4 + 88 – 47 ÷ 6 + 8}^(1/2)

A) 23

B) 27

C) 17

D) 33

Question 5: Find the simplified value of the given expression:

A) 12/5

B) 27/5

C) 27/7

D) 12/7

Question 6: Find the simplified value of the given expression.

A) 180

B) 162

C) 154

D) 160

Question 7: Find the simplified value of the given expression.

75 ÷ 2.5 of 3 X 6 – 2.4 ÷ 0.6 X 10 + 2.6 – 1.4 + 2.8 – 2

A) 24

B) 20

C) 26

D) 22

Question 8: Find the simplified value of the given expression:

A) 71

B) 53

C) 128

D) 34

Question 9: Find the simplified value of the given expression:

A) 1

B) 2

C) 4

D) 5

Question 10: If √2 = 1.414, then find the value of 

A) 2.01

B) 3.01

C) 4.01

D) 7.07

Simplification Questions in the Hindi Language

प्रश्न 1: दिए गए समीकरण का सरलीकृत मान ज्ञात कीजिए:

A) 16

B) 12

C) 20

D) 10

प्रश्न 2: दिए गए समीकरण का सरलीकृत मान ज्ञात कीजिए।

182 ÷ 13 X 2 of 2.5 – 20 ÷ 5 X 2.5 – 17.7 + 2.7

A) 43

B) 42.4

C) 45

D) 46.2

प्रश्न 3: दिए गए समीकरण का सरलीकृत मान ज्ञात कीजिए।

A) 11

B) 15

C) 22

D) 10

प्रश्न 4: हल करें: {(25)² + 24 ÷ 18 – 6 × 8 of 4 + (13 × 2) ÷ 4 + 88 – 47 ÷ 6 + 8}^(1/2)

A) 23

B) 27

C) 17

D) 33

प्रश्न 5: दिए गए समीकरण का सरलीकृत मान ज्ञात कीजिए:

A) 12/5

B) 27/5

C) 27/7

D) 12/7

प्रश्न 6: दिए गए समीकरण का सरलीकृत मान ज्ञात करें।

A) 180

B) 162

C) 154

D) 160

प्रश्न 7: दिए गए समीकरण का सरलीकृत मान ज्ञात कीजिए।

75 ÷ 2.5 of 3 X 6 – 2.4 ÷ 0.6 X 10 + 2.6 – 1.4 + 2.8 – 2

A) 24

B) 20

C) 26

D) 22

प्रश्न 8: दिए गए समीकरण का सरलीकृत मान ज्ञात कीजिए:

A) 71

B) 53

C) 128

D) 34

प्रश्न 9: दिए गए समीकरण का सरलीकृत मान ज्ञात करें:

A) 1

B) 2

C) 4

D) 5

प्रश्न 10: यदि √2 = 1.414 है तो 

 का मान ज्ञात कीजिए:

A) 2.01

B) 3.01

C) 4.01

D) 7.07

ANSWER KEYS and SOLUTIONS:

Solutions of the Above Questions with Explanation

Solution 1: 4)

Hence, option d.

Solution 2: 3)

Given, 182 ÷ 13 X 2 of 2.5 – 20 ÷ 5 X 2.5 – 17.7 + 2.7

= 182 ÷ 13 X 5 – 20 ÷ 5 X 2.5 – 17.7 + 2.7

= 14 X 5 – 4 X 2.5 – 17.7 + 2.7

= 70 – 10 – 17.7 + 2.7

= 72.7 – 27.7

= 45

Hence, option c

Solution 3: 4)

Hence, option d

Solution 4: 1)

(25)² + 24 ÷ 18 – 6 × 8 of 4 + (13 × 2) ÷ 4 + 88 – 47 ÷ 6 + 8 = 625 + (4/3) – 6 × 32 + (13/2) + 88 – (47/6) + 8

= 625 + (4/3) – 192 + (13/2) + 88 – (47/6) + 8 = 721 – 192 + (47/6) – (47/6) = 529

Desired answer = √529 = 23

Hence, option a.

Solution 5: 2)

Hence, option b.

Solution 6: 2)

Hence, option b

Solution 7: 4)

Applying BODMAS,

75 ÷ 2.5 of 3 X 6 – 2.4 ÷ 0.6 X 10 + 2.6 – 1.4 + 2.8 – 2

= 75 ÷ 7.5 X 6 – 2.4 ÷ 0.6 X 10 + 2.6 – 1.4 + 2.8 – 2

= 10 X 6 – 4 X 10 + 2.6 – 1.4 + 2.8 – 2

= 60 – 40 + 2.6 – 1.4 + 2.8 – 2

= 65.4 – 43.4

= 22

Hence, option d.

Solution 8: 2)

Hence, option b.

Solution 9: 2)

= 2

Hence, option b.

Solution 10: 2)

Given that,

Hence, option b.

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