Ratio & Proportion For RBI Grade B Exam

Ratio & Proportion For RBI Grade B Exam is a fundamental topic covered in Quantitative Aptitude section. A total of 30 questions carrying a value of 30 marks are asked in Quantitative Aptitude paper. In RBI Grade B Phase 1, Candidates get 120 minutes time for 200 questions from subjects English, Reasoning, Quantitative Aptitude, and General Awareness. We provided questions for practice in Ratio & Proportion section with detailed solution. It is a basic topic covered in RBI Grade B Phase 1. Begin your questions practice with latest pattern provided in this blog.

Important Formulas To Know For Ratio & Proportion

Ratio & Proportion is a basic fundamental topic to start studying for RBI Grade B Phase 1 Quantitative Aptitude section. Candidates can check the table to get Ratio & Proportion topics and explanation provided in brief. You can get through the table to understand basic topics. Then, begin solving questions covered with detailed solutions.

Questions For Ratio & Proportion For RBI Grade B Exam

Candidates should start preparing for Ratio & Proportion For RBI Grade B Exam with a list of questions provided in this section. We provided questions with detailed solutions for the convenience of candidates to improve their performance in RBI Grade B Phase 1 Exam 2024.

Question 1: After 8 years, the ratio of age of A to B will be 6:7. Age of B, 8 years ago was 20% more than age of A, 7 years ago. If the present average age of A, B, and C is 58 years then find the ratio of the age of A after 18 years to the present age of C.

A) 6:7

B) 7:6

C) 4:5

D) 5:4

E) None of these

Question 2: There are two friends A and B, and the ratio of the incomes of A to B is 7:12. A invests 20% of the salary in mutual funds and spends remaining amount. B invests 30% of the income in mutual fund and spends remaining amount. If the total amount that A and B spend is Rs. 28000, find the income of A.

A) Rs. 10000

B) Rs. 12000

C) Rs. 14000

D) Rs. 18000

E) Rs. 16000

Question 3: Ratio of age of Ramesh and Suresh after 8 years is 7:5 respectively. Age of Mukesh after 15 years will be 150% more than age of Suresh, eight years ago. If present average age of Ramesh and Mukesh is 46.5 years then find present age of Suresh.

A) 48 years

B) 45 years

C) 36 years

D) 32 years

E) 40 years

Question 4: Arun bought ‘x + 12’ kg of rice at Rs. ‘x + 24’ per kg and ‘x’ kg of pulse at Rs. ‘x + 34’ per kg and mixed them together and sold the resulting mixture at a rate of Rs. 65 per kg by making a profit of 25%. Find the value of x.

A) 20

B) 28

C) 24

D) 18

E) 16

Question 5: The ratio of present ages of ‘A’ and ‘B’ is 6:5, respectively. 16 years hence, the ratio of their ages becomes 22:19, respectively. Find the ratio of their ages 12 years ago from now.

A) 6:5

B) 8:7

C) 3:2

D) 5:4

E) None of these

Solutions

Solution 1: B)

Let age of A and B after 8 years is 6x years and 7x years respectively.

According to question;

(7x – 16) = 1.2 × (6x – 15)

7x – 16 = 7.2x – 18

0.2x = 2

x = 10

Present age of A = 6 × 10 – 8 = 52 years

Present age of B = 7 × 10 – 8 = 62 years

Present age of C = 58 × 3 – 52 – 62 = 60 years

Desired ratio = (52 + 18):60 = 7:6

Hence, option b.

Solution 2: C)

Let the income of A = Rs. 7x

Income of B = Rs. 12x

According to the question,

7x × 80% + 12x × 70% = 28000

5.6x + 8.4x = 28000

14x = 28000

x = 2000

Income of A = 7x = Rs. 14000

Hence, option c.

Solution 3: D)

Let age of Ramesh and Suresh after 8 years will be 7x years and 5x years respectively.

Let present age of Mukesh is ‘y’ years.

According to question;

y + 15 = 2.5 × (5x – 16)

y + 15 = 12.5x – 40

y = 12.5x – 55………………………….(1)

And, (7x – 8 + y)/2 = 46.5

7x + y – 8 = 93

7x + y = 101

7x + 12.5x – 55 = 101 [From (1)]

19.5x = 156

x = 8

Present age of Suresh = 8 × 5 – 8 = 32 years

Hence, option d.

Solution 4: C)

Cost price of the mixture = 65/1.25 = Rs. 52 per kg

According to question;

(x + 12)(x + 24) + x(x + 34) = 52(x + 12 + x)

Or, x² + 36x + 288 + x² + 34x = 104x + 624

Or, 2x² – 34x – 336 = 0

Or, x² – 17x – 168 = 0

Or, x² – 24x + 7x – 168 = 0

Or, x(x – 24) + 7(x – 24) = 0

Or, (x – 24)(x + 7) = 0

Or, x = 24

Hence, option c.

Solution 5: D)

Let the present ages of ‘A’ and ‘B’ be 6x years and 5x years, respectively

According to the question,

(6x + 16)/(5x + 16) = 22/19

Or, 114x + 304 = 110x + 352

Or, 4x = 48

Or, x = 12

Therefore, age of ‘A’, 12 years ago from now = 6x – 12 = 60 years

Age of ‘B’, 12 years ago from now = 5x – 12 = 48 years

Required ratio = 60:48 = 5:4

Hence, option d.

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