Percentage For IBPS RRB- Percentage is not a separate topic; it is a small topic quantitative from which some questions come in the exam. The percentage is an easy section; you need to understand everything briefly so that candidates score good marks in the IBPS RRB quantitative section. The percentage is denoted with this % symbol. If we find the percentage of any digit, it is solved by putting 100 in its place. For example, if we want to find the percentage of 75, it becomes 75/100, and after solving it, it will be written as 1/3. Candidates can bookmark our article and check tips, tricks, and practical questions in the article below.
Here we are sharing some fraction values candidates check all details in the table below.
Percentage value | Fraction Form |
100% | 1 |
50% | (1/2) |
33× 1/3 % or 33.33% | (1/3) |
25% | (1/4) |
20% | (1/5) |
16×2/3% 16.66 | (1/6) |
14×2/7% or 14.28% | (1/7) |
12.5% | (1/8) |
11× 1/9 %or 11.11% | (1/9) |
10% | (1/10) |
9×1/11% or 9.09% | (1/11) |
8× 1/3 % or 8.33% | (1/12) |
Definition and Basic Formula:
Question 1: Heena got 35% marks in an exam and failed by 30 marks. If passing marks is 240, then find the total marks in the exam.
A) 500
B) 600
C) 700
D) 800
E) 750
Question 2: Length of a rectangle is increased by 20%. By how much percent breadth should be increased/decreased so that area remains the same.
A) 15%
B) 20%
C) 25%
D) 16.67%
E) 33.33%
Question 3: In a library there are five kinds of books, out of them 16% are in Hindi, 30% are in English, 18% are in Urdu, 24% are in Pharsi and rest 150 books are in Maithili. Find total amount of books in the library.
A) 1450
B) 1350
C) 1150
D) 1250
E) None of these
Question 4: The population of town increases by 12.5% with respect to previous year and becomes 9000. If the ratio of males to females in the previous year is 11:5, then find the number of males in previous year.
A) 4400
B) 5500
C) 6600
D) 3800
E) None of these
Question 5: In an examination, Mayank got 28% marks but failed by x marks. In the same examination, Tushar got 45% marks and thus able to score ‘x + 12’ marks above passing marks. Find the marks obtained by Mayank if the passing percentage of the examination is 36%.
A) 240
B) 326
C) 432
D) 448
E) None of these
Question 6: A man gives 20% of his salary to his mother. His mother distributed all the amount received by his son to her three daughters in the ratio of 4:7:3. If the maximum amount received by her daughter is Rs. 500, then find the salary of man.
A) Rs. 4500
B) Rs. 5600
C) Rs. 5200
D) Rs. 6000
E) Rs. 5000
Question 7: Abhinay spent 34% of his monthly income on entertainment, 22% on fooding, 18% on studies, 12% on clothing and rest on travelling. Difference between the amount spent on entertainment and travelling is Rs. 3600. Find amount spent on fooding.
A) Rs. 3960
B) Rs. 4120
C) Rs. 2820
D) Rs. 2540
E) Rs. 3690
Question 8: If the price of a commodity is increased by 35%, and its consumption is decreased by (100/3)%, then find the percentage decrease in the expenditure on that commodity.
A) 10%
B) 12.5%
C) 14%
D) 15%
E) 17.5%
Question 9: In 2016, 60% of the people who went Manali were males. If the number of females who went to Manali was 992, then find the total number of people who visited Manali in 2016.
A) 2560
B) 2480
C) 2320
D) 2140
E) 2400
Question 10: Monthly income of Manish is Rs. 12,800 and his monthly expenditure is Rs. 4,000. If his income is decreased by 25% and expenditure is decreased by Rs. 1,000, then find the change in his monthly savings?
A) Rs. 1,800
B) Rs. 1,600
C) Rs. 1,400
D) Rs. 2,200
E) None of these
Solution 1: B)
Let, total marks be ‘x’
So, 0.35x + 30 = 240
0.35x = 210
x = 600
Hence, option b.
Solution 2: D)
Let length of the rectangle be 50 cm
Breadth of the rectangle be y cm
New breadth be ‘b’ cm.
Original area = 50y cm2
New length = 1.2 × 50 = 60 cm
According to question,
New Area = 60b
60 × b = 50y
b = 50y/60 = 5y/6
Desired decrease = [(y – 5y/6)/y] × 100 = 1/6 × 100 = 16.67%
Hence, option d.
Solution 3: D)
Let total number of books in the library be x
Percentage of Maithili books in the library = 100 – (16 + 30 + 18 + 24) = 100 – 88 = 12%
According to question,
0.12x = 150
x = 150/0.12 = 1250
Hence, option d.
Solution 4: B)
Population of town in the previous year = 9000/1.125 = 8000
So, male population in the previous year = 11/16 × 8000 = 5500
Hence, option b.
Solution 5: E)
Let the maximum marks of the examination = y
So, the passing marks of the examination = 0.36y
Marks secured by Mayank = 0.28y = 0.36y – x
x = 0.08y
Marks secured by Tushar = 0.45y = 0.36y + x + 12
x + 12 = 0.09y
0.08y + 12 = 0.09y
0.01y = 12
y = 1200
x = 0.08 × 1200
x = 96
So, the marks obtained by Mayank = 0.28 × 1200 = 336
Hence, option e.
Solution 6: E)
Amount received by mother = 500/7 * 14 = Rs. 1000
Salary of man = 1000/0.2 = Rs. 5000
Hence, option e.
Solution 7: A)
Let monthly income of Abhinay is Rs. 100x
Percentage of amount spent on travelling = 100 – 34 – 22 – 18 – 12 = 14%
According to question
0.34 × 100x – 0.14 × 100x = 3600
34x – 14x = 3600
20x = 3600
x = 180
Monthly income of Abhinay = Rs. 18000
Money spent on fooding = 0.22 × 18000 = Rs. 3960
Hence, option a.
Solution 8: A)
Let initial price be Rs. 100 and initial consumption be 30 units.
So, initial expenditure = 100 × 30 = Rs. 3000
Increased price = 1.35 × 100 = Rs. 135
Decreased consumption = (2/3) × 30 = 20 units
New expenditure = 135 × 20 = Rs. 2700
Decrease in expenditure = 3000 – 2700 = Rs. 300
Percentage decrease = 300/3000 × 100 = 10%
Hence, option a.
Solution 9: B)
Total number of people who visited Manali = 992/0.4 = 2480
Hence, option b.
Solution 10: D)
Monthly savings of Manish earlier = 12800 – 4000 = Rs. 8,800
Monthly income of Manish now = 0.75 × 12800 = Rs. 9,600
Monthly expenditure of Manish now = 4000 – 1000 = Rs. 3,000
Monthly savings of Manish now = 9600 – 3000 = Rs. 6,600
Desired change = 8800 – 6600 = Rs. 2,200
Hence, option d.
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A percentage is a fraction expressed with a denominator of 100. It represents a part of a whole and is denoted by the symbol %.
The percentage of a number can be calculated using the formula: Percentage= (Actual value/total value) × 100
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