Inequalities questions for SBI PO: The questions of inequality are part of the reasoning section. Although, they are not asked in SBI PO mains but are deot to avoid them. finitely asked in SBI PO prelims. So, it’s better not to avoid them.
Inequalities questions for SBI PO 2021 Prelims Practice
Question 1: In the question, assuming the given statements to be true, find which of the conclusion (s) among given three conclusions is /are definitely true and then give your answer accordingly.
Statements: Y>O≥S≤T; S ≥ K≥H < V
Conclusions:
I. Y>V
II. T ≥H
III. H≤O
a. Only conclusion I is true.
b. Only conclusions I and III are true.
c. Only conclusion II is true.
d. Only conclusions II and III are true.
e. All conclusions I, II and III are false.
Answer: d
Solution:
Given statements: Y>O≥S≤T; S ≥ K≥H < V
On combining, we get
Y>O≥S ≥ K≥H < V; T ≥ S ≥ K≥H < V
Conclusions:
I. Y>V: False (As Y>O≥S ≥ K≥H < V, the relation between Y and V cannot be determined)
II. T≥H: True (As T ≥ S ≥ K≥H, so, T≥H)
III. H≤O: True (As O≥S ≥ K≥H, so, O ≥ H)
Hence, option d.
Question 2: In the question, assuming the given statements to be true, find which of the conclusion (s) among given three conclusions is /are definitely true and then give your answer accordingly.
Statements: B ≥ K = T; X < B ≤ M; G > K > F
Conclusions:
I. F < X
II. M ≥ K
III. B > F
a. Only conclusion I is true.
b. Only conclusions II and III are true.
c. Only conclusion II is true.
d. Only conclusions I and II are true.
e. All conclusions I, II and III are false.
Answer: b
Solution:
Given statements: B ≥ K = T; X < B ≤ M; G > K > F
On combining, we get
X < B ≥ K > F; T = K ≤ B > X; M ≥ B ≥ K > F
Conclusions:
I. F < X: False (As X < B ≥ K > F, the relation between F and X can’t be determined)
II. M ≥ K: True (As M ≥ B ≥ K, so M ≥ K)
III. B > F: True (As B ≥ K > F, so B > F)
Hence, option b.
Question 3: Which of the following should be placed in the blank spaces respectively ( in the same order from left to right) in order to complete the given expression in such a manner that makes the expression ‘P > Q’ definitely false?
__ > __ < __ ≤ __ > __ ≤ __
a. U, T, P, S, R, Q
b. P, T, S, Q, R, U
c. T, P, U, Q, S, R
d. P, R, Q, T, S, U
e. None of the above
Answer: c
Solution:
i. Putting the option (a) values to the equation, we get U > T < P ≤ S > R ≤ Q, here P > Q is not definitely false.
ii. Putting the option (b) values to the equation, we get P > T < S ≤ Q > R ≤ U, here P > Q is not definitely false.
iii. Putting the option (c) values to the equation, we get T > P < U ≤ Q > S ≤ R, here P > Q is definitely false.
iv. Putting the option (d) values to the equation, we get P > R < Q ≤ T > S ≤ U, here P > Q is not definitely false.
Hence, option c.
Question 4: Which of the following symbols should replace the question marks (?) in the given expression in order to make the expressions ‘A ≥ C’ definitely true?
G > C (?) E ≤ D; B > A ≥ D
a. ≥
b. <
c. >
d. None of these
e. ≤
i. Replacing the signs of option (a) in the given inequality, G > C ≥ E ≤ D; B > A ≥ D, it doesn’t satisfy the given condition.
ii. Replacing the signs of option (c) in the given inequality, G > C < E ≤ D; B > A ≥ D, it doesn’t satisfy the given condition.
iii. Replacing the signs of option (d) in the given inequality, G > C > E ≤ D; B > A ≥ D, it doesn’t satisfy the given condition.
iv. Replacing the signs of option (e) in the given inequality, G > C ≤ E ≤ D; B > A ≥ D, it satisfies the given condition.
Hence, option e.
CODED INEQUALITIES:
Directions (5-6): Answer the questions based on the information given below.
If ‘>’ is denoted as ‘#’
‘≥’ is denoted as ‘&’
‘=’ is denoted as ‘$’
‘≤’ is denoted as ‘%’
And ‘<’ is denoted as ‘@’
Question 5: Statement: O&N#P$S; N@R$L%T; L#Q$U
Conclusions:
I. Q # P
II. U @ T
III. R # T
a. Only conclusion I is true.
b. Only conclusion II is true
c. Either conclusion I or III and II are true
d. Both conclusions II and III are true.
e. All the conclusions I, II and III are true.
Answer: b
Solution:
Decoding the signs of the statements, statement becomes
O ≥ N > P = S; N < R = L ≤ T; L > Q = U
On combining, we get
Q < L = R > N > P and T ≥ L > Q = U
Conclusions:
I. Q # P means Q > P: False (As, Q < L = R > N > P)
II. U @ T means U < T: True (As, T ≥ L > Q = U)
III. R # T means R > T: False (As, R = L ≤ T, so, R ≤ T)
Hence option b.
Question 6: Statement: R@U%Q$T; Q#L&M; N$M@O
Conclusions:
I. R @ M
II. Q # N
III. L $ T
a. Only conclusion I is true.
b. Only conclusion II is true
c. Only conclusions I and II is true
d. Only conclusions I and III are true.
e. All conclusion I, II and III are true.
Answer: b
Solution:
Decoding the signs of the statements, statement becomes
R < U ≤ Q = T; Q > L ≥ M; N = M < O
On combining, we get
R< Q > M and N = M ≤ L < Q = T
Conclusions:
I. R @ M means R < M: False (As, R< Q > M)
II. Q # N means Q > N: True (As, N = M ≤ L < Q = T)
III. L $ T means L = T: False (As, N = M ≤ L < Q = T)
Hence option b.
We hope Inequalities questions for SBI PO were good enough.
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