The IBPS RRB 2021 notification is not out yet. As far as previous year vacancies are concerned there were 4624 vacancies. Those who are waiting for this year’s notification must start giving free mock test as a part of their preparation strategy. This year the recruitment notification got delayed because of the COVID-19 pandemic which is still prevailing in the country. The IBPS calendar 2021 has been released earlier this year for which we are giving the details of the tentative exams below.
Numerical Ability is one of the major sections of IBPS RRB Clerk Prelims exam. As far as the RRB Clerk Prelims 2021 exam pattern there are only two sections including Reasoning and Numerical Ability. In this article we will list down few important numerical ability topics for IBPS RRB Clerk Prelims 2021 exam and will also include their practice questions. Let’s first take a strategic look at the RRB Clerk Prelims 2021 exam pattern and important dates first.
Sr. No. | Activity | IBPS RRB Exam Dates |
---|---|---|
1 | Online Examination – Preliminary | Officer Scale I and Office Assistants : 01.08.2021, 07.08.2021, 08.08.2021, 14.08.2021 and 21.08.2021 |
2 | Single Examination | Officers Scale II & III : 25.09.2021 |
2 | Online Examination – Main | Officer Scale I : 25.09.2021 Office Assistants : 03.10.2021 |
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Keeping in mind the above exam pattern, candidates have to give equal weightage to both the reasoning as well as numerical ability sections. However, here we are with few important numerical ability topics along with their practice questions.
RRB Clerk Prelims 2021 Numerical Ability Important Topics
These are few important topics and are to be revised thoroughly. Mentioned below are practice questions related to these important topics.
RRB Clerk Prelims Free Mock Test 2021
Let’s now check out few practice questions related to each of the important topics mentioned above for RRB Clerk Prelims 2021 exam.
Data Interpretation forms a major part of the Quantitative Aptitude section for all major banking exams. In the exact sense Data Interpretation means making sense out of the numerical that has been collected and analyzed. As far as data interpretation questions are concerned majority of questions asked from DI are based on the following:
In order to attempt DI questions in the most accurate manner it is extremely important that the above mentioned concepts are clear.
Directions: Answer the questions based on the information given below. The bar graph given below shows the number of male visitors and female visitors to Sukhdev Da Dhaba on Monday, Tuesday, Wednesday, Thursday and Friday, respectively.
Common Solution:
Days | Male Visitors | Female visitors | Total visitors |
Monday | 160 | 140 | 300 |
Tuesday | 200 | 120 | 320 |
Wednesday | 180 | 220 | 400 |
Thursday | 240 | 180 | 420 |
Friday | 220 | 160 | 380 |
Practice Quant Topic Wise Quizzes
1. What is the average of number of male visitors visiting on each of the given day?
a) 200
b) 160
c) 150
d) 180
e) None of these
Ans: a
Solution:
Desired average = (160 + 200 + 180 + 240 + 220)/5 = 200
Hence, option a.
2. What is the ratio of male visitors on Monday and Tuesday together to female visitors on Wednesday and Thursday together?
a) 8:9
b) 9:10
c) 5:7
d) 3:5
e) None of these
Ans: b
Solution:
Desired ratio = (160 + 200):(220 + 180) = 360:400 = 9:10
Hence, option b
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Here we are talking about Mixture and Alligations which is more or less asked in almost every banking exam. The rules of mixture and alligations basically help the candidates to find out proportion between the two commodities given. These are two different terms and need to be understood differently.
1. A vessel contains 540 litres mixture of honey, milk and water in the ratio of 3:4:5 respectively. 15 litres of honey and 20 litres of milk is added to this mixture. Find the new ratio of honey, milk and water in the vessel.
a. 7:2:8
b. 2:3:5
c. 6:8:9
d. 4:5:3
e. 7:8:9
Answer: c)
Solution:
Quantity of honey in vessel initially = [3/ (3 + 4 + 5)] × 540 = 135 litres
Quantity of milk in vessel initially = [4/ (3 + 4 + 5)] × 540 = 180 litres
Quantity of water in vessel initially = [5/ (3 + 4 + 5)] × 540 = 225 litres
Therefore, required ratio = (135 + 15): (180 + 20): 225 = 150: 200: 225 = 6: 8: 9
Hence, option c.
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3. A vessel contains 240 litres mixture of milk and water in the ratio of 5:3. How much water should be added to this vessel so that ratio of milk and water changes to 1:1?
a. 72 litres
b. 40 litres
c. 60 litres
d. 54 litres
e. 45 litres
Answer: c)
Solution:
Amount of milk in vessel = (5/8) × 240 = 150 litres
Amount of water in vessel = (3/8) × 240 = 90 litres
Let, required amount of water be x litres
According to question,
150: (90 + x) = 1: 1
150 = 90 + x
x = 150 – 90
x = 60 litres
Hence, option c.
Practice Quant Topic Wise Quizzes
Questions on this topic are perhaps the easiest in the complete quantitative ability section. You need to follow the BODMAS rule when attempting these questions. You should go from left to right on BODMAS rule when attempting simplification question. You should be extremely good in approximation and rounding off numbers. Mentioning below are few practice questions for RRB Clerk Prelims 2021.
2. What will come in the place of question mark (?) in the given expression?
45% of 480 + 182 = ?2 – 172 + 102
a. 25
b. 30
c. 27
d. 32
e. 22
Answer: c)
Solution:
45% of 480 + 182 = ?2 – 172 + 102
?2 – 289 + 100 = 0.45 × 480 + 324
?2 – 189 = 216 + 324
?2 = 540 + 189
?= √729
? = 27
Hence, option c.
Practice Quant Topic Wise Quizzes
3. What will come in the place of question mark (?) in the given expression?
(210 ÷ 14) × 15 + 252 = ?2 – 20% of 555
a. 27
b. 31
c. 36
d. 24
e. 18
Answer: b)
Solution:
(210 ÷ 14) × 15 + 252 = ?2 – 20% of 555
?2 – (1/5) × 555 = 15 × 15 + 625
?2 – 111= 225 + 625
?2 =850 + 111
? = √961= 31
Hence, option b.
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1. A certain sum of money invested at 20% per annum for 2 years compounded annually, but if interest would have been compounded half yearly on the same amount, then Rs. 241 more interest would have been received. Find the sum of money invested.
a. Rs. 10000
b. Rs. 8000
c. Rs. 12000
d. Rs. 7500
e. Rs. 10500
Answer: a
Solution:
Let the certain amount of money invested be Rs.‘P’.
When interest is compounded yearly,
So, CI = P(1 + 20/100)2 – P = P[(1 + 20/100) 2 – 1] = P(1.44 – 1) = 0.44 × P
When interest is compounded half yearly,
And, CI = P(1 + 10/100) 4 – P = P[(1.1) 4 – 1] = P(1.4641 – 1) = 0.4641 × P
According to question, 0.4641×P – 0.44×P = 241
0.0241×P = 241
P = 241/0.0241 = 10000
Therefore, the certain amount of money invested is Rs. 10000.
Hence, option a.
RRB Clerk Prelims Free Mock Test 2021
This brings us to the end of this article. So, keep practicing these numerical ability questions and ace the quant section for the upcoming RRB Clerk Prelims 2021 examination.
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