IBPS Clerk prelims examination is to be held in the month of August/September and lately the last date of online registration has been extended till 28th July, 2023. For better preparation for IBPS Clerk Prelims exam it is important to go through all important and scoring topics thoroughly. Many people find quant as a difficult and lengthy section, but at the same time it is extremely scoring. So, for those who have difficulty in quant section and have discovered this blog have actually landed at the right place. Here we have got for you IBPS Clerk prelims quant scoring topics along with practice questions for those topics.
IBPS Clerk Prelims Free Mock Test
Subjects | No. of Questions | Marks | Duration |
English Language | 30 | 30 | 20 mins |
Quantitative Aptitude | 35 | 35 | 20 mins |
Reasoning Ability | 35 | 35 | 20 mins |
Total | 100 questions | 100 marks | 60 mins |
Some of the hot or you can scoring or important quant topics for IBPS Clerk prelims exam is mentioned below:
Number Series
Question 1: What will come in place of the question mark (?) in the following series?
11, 20, 31, 44, ?, 76
A) 63
B) 69
C) 45
D) 59
E) 49
Question 2: What will come in place of the question mark (?) in the following series?
13, 3, 18, 8, 23, ?
A) 13
B) 21
C) 28
D) 33
E) 3
Question 3: What will come in place of the question mark (?) in the following series?
12, 18, 30, 42, ?, 78
A) 52
B) 64
C) 72
D) 60
E) 66
Question 4: What will come in place of the question mark (?) in the following series?
200, 187, 174, ?, 148, 135
A) 158
B) 161
C) 151
D) 154
E) 164
Question 5: What will come in place of the question mark (?) in the following series?
3600, ?, 120, 30, 10, 5
A) 600
B) 300
C) 1200
D) 720
E) 240
IBPS Clerk Prelims Free Mock Test
Simplification
Question 6: What will come in the place of question mark (?) in the given expression?
16% of 250 + 32% of 500 = ?
A) 200
B) 180
C) 160
D) 220
E) 175
Question 7: What will come in the place of question mark (?) in the given expression?
? = 12 × 13 ÷ 3 + (2)3
A) 55
B) 65
C) 60
D) 75
E) 70
Question 8: What will come in the place of question mark (?) in the given expression?
25% of 120 + √225 + (2)2 = ?2
A) 8
B) 9
C) 7
D) 5
E) 6
Question 9: What will come in the place of question mark (?) in the given expression?
3 × ?2 = 36 + 15 + 100 – 43
A) 8
B) 6
C) 7
D) 4
E) 2
Question 10: What will come in the place of question mark (?) in the given expression?
28 + √144 + 144 ÷ (3)2 = ? – 4
A) 75
B) 64
C) 72
D) 80
E) 60
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Approximation
Question 11: What approximate value will come in place of the question mark (?) in the following question?(Note: You are not expected to calculate the exact value.)
9.252 + (108.48 ÷ 3.89) = √? × 8.76
A) 50
B) 140
C) 180
D) 80
E) 200
Question 12: What approximate value will come in place of the question mark (?) in the following question?(Note: You are not expected to calculate the exact value.)
14.992 – (299.78 ÷ 12.25) = ? × 4.89
A) 20
B) 40
C) 60
D) 90
E) 120
Question 13: What approximate value will come in place of the question mark (?) in the following question?(Note: You are not expected to calculate the exact value.)
(7/12) × 179.89 + (15.34 × 4.89) = ?
A) 180
B) 210
C) 150
D) 120
E) 240
Question 14: What approximate value will come in place of the question mark (?) in the following question?(Note: You are not expected to calculate the exact value.)
(√364 + 120.78) ÷ 6.78 = ? ÷ 3.88
A) 100
B) 40
C) 20
D) 80
E) 150
Question 15: What approximate value will come in place of the question mark (?) in the following question?(Note: You are not expected to calculate the exact value.)
14.89% of 399.76 + (479.76 ÷ 12.34) = ?
A) 100
B) 150
C) 120
D) 60
E) 160
IBPS Clerk Prelims Free Mock Test
Equation Comparison
Question 16: In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y and choose the correct option.
I. x2 = 49
II. y2 + 8y = 0
A) x > y
B) x < y
C) x = y or the relationship cannot be established
D) x ≥ y
E) x ≤ y
Question 17: In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y and choose the correct option.
I. x3 = -729
II. y2 + 13y + 40 = 0
A) x > y
B) x < y
C) x = y or the relationship cannot be established
D) x ≥ y
E) x ≤ y
Question 18: In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y and choose the correct option.
I. x2 – x = 6
II. y2 + 7y + 10 = 0
A) x > y
B) x < y
C) x = y or the relationship cannot be established
D) x ≥ y
E) x ≤ y
Question 19: In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y and choose the correct option.
I. x2 – 25 = 0
II. y3 = -216
A) x > y
B) x < y
C) x = y or the relationship cannot be established
D) x ≥ y
E) x ≤ y
Question 20: In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y and choose the correct option.
I. x2 + 13x + 42 = 0
II. y2 + 15y + 56 = 0
A) x > y
B) x < y
C) x = y or the relationship cannot be established
D) x ≥ y
E) x ≤ y
प्रश्न 1: निम्नलिखित श्रृंखला में प्रश्नवाचक चिन्ह (?) के स्थान पर क्या आएगा?
11, 20, 31, 44, ?, 76
A) 63
B) 69
C) 45
D) 59
E) 49
प्रश्न 2: निम्नलिखित श्रृंखला में प्रश्नवाचक चिन्ह (?) के स्थान पर क्या आएगा?
13, 3, 18, 8, 23, ?
A) 13
B) 21
C) 28
D) 33
E) 3
प्रश्न 3: निम्नलिखित श्रृंखला में प्रश्नवाचक चिन्ह (?) के स्थान पर क्या आएगा?
12, 18, 30, 42, ?, 78
A) 52
B) 64
C) 72
D) 60
E) 66
IBPS Clerk Prelims Free Mock Test
प्रश्न 4: निम्नलिखित श्रृंखला में प्रश्नवाचक चिन्ह (?) के स्थान पर क्या आएगा?
200, 187, 174, ?, 148, 135
A) 158
B) 161
C) 151
D) 154
E) 164
प्रश्न 5: निम्नलिखित श्रृंखला में प्रश्नवाचक चिन्ह (?) के स्थान पर क्या आएगा?
3600, ?, 120, 30, 10, 5
A) 600
B) 300
C) 1200
D) 720
E) 240
प्रश्न 6: दिए गए समीकरण में प्रश्नवाचक चिन्ह (?) के स्थान पर क्या आएगा?
16% of 250 + 32% of 500 = ?
A) 200
B) 180
C) 160
D) 220
E) 175
प्रश्न 7: दिए गए समीकरण में प्रश्नवाचक चिन्ह (?) के स्थान पर क्या आएगा?
? = 12 × 13 ÷ 3 + (2)3
A) 55
B) 65
C) 60
D) 75
E) 70
प्रश्न 8: दिए गए समीकरण में प्रश्नवाचक चिन्ह (?) के स्थान पर क्या आएगा?
25% of 120 + √225 + (2)2 = ?2
A) 8
B) 9
C) 7
D) 5
E) 6
प्रश्न 9: दिए गए समीकरण में प्रश्नवाचक चिन्ह (?) के स्थान पर क्या आएगा?
3 × ?2 = 36 + 15 + 100 – 43
A) 8
B) 6
C) 7
D) 4
E) 2
प्रश्न 10: दिए गए समीकरण में प्रश्नवाचक चिन्ह (?) के स्थान पर क्या आएगा?
28 + √144 + 144 ÷ (3)2 = ? – 4
A) 75
B) 64
C) 72
D) 80
E) 60
प्रश्न 11: निम्नलिखित प्रश्न में प्रश्न चिह्न (?) के स्थान पर क्या अनुमानित मान आएगा? (नोट: आपको सटीक मान की गणना करने की आवश्यकता नहीं है।)
9.252 + (108.48 ÷ 3.89) = √? × 8.76
A) 50
B) 140
C) 180
D) 80
E) 200
प्रश्न 12: निम्नलिखित प्रश्न में प्रश्न चिह्न (?) के स्थान पर क्या अनुमानित मान आएगा? (नोट: आपको सटीक मान की गणना करने की आवश्यकता नहीं है।)
14.992 – (299.78 ÷ 12.25) = ? × 4.89
A) 20
B) 40
C) 60
D) 90
E) 120
प्रश्न 13: निम्नलिखित प्रश्न में प्रश्न चिह्न (?) के स्थान पर क्या अनुमानित मान आएगा? (नोट: आपको सटीक मान की गणना करने की आवश्यकता नहीं है।)
(7/12) × 179.89 + (15.34 × 4.89) = ?
A) 180
B) 210
C) 150
D) 120
E) 240
प्रश्न 14: निम्नलिखित प्रश्न में प्रश्न चिह्न (?) के स्थान पर क्या अनुमानित मान आएगा? (नोट: आपको सटीक मान की गणना करने की आवश्यकता नहीं है।)
(√364 + 120.78) ÷ 6.78 = ? ÷ 3.88
A) 100
B) 40
C) 20
D) 80
E) 150
IBPS Clerk Prelims Free Mock Test
प्रश्न 15: निम्नलिखित प्रश्न में प्रश्न चिह्न (?) के स्थान पर क्या अनुमानित मान आएगा? (नोट: आपको सटीक मान की गणना करने की आवश्यकता नहीं है।)
14.89% of 399.76 + (479.76 ÷ 12.34) = ?
A) 100
B) 150
C) 120
D) 60
E) 160
प्रश्न 16: प्रश्न में, दो समीकरण I और II दिए गए हैं। आपको x और y के बीच सही संबंध स्थापित करने और सही विकल्प चुनने के लिए दोनों समीकरणों को हल करना होगा।
I. x2 = 49
II. y2 + 8y = 0
A) x > y
B) x < y
C) x = y या सम्बस्न्ध स्थापित नहीं किया जा सकता
D) x ≥ y
E) x ≤ y
प्रश्न 17: प्रश्न में, दो समीकरण I और II दिए गए हैं। आपको x और y के बीच सही संबंध स्थापित करने और सही विकल्प चुनने के लिए दोनों समीकरणों को हल करना होगा।
I. x3 = -729
II. y2 + 13y + 40 = 0
A) x > y
B) x < y
C) x = y या सम्बन्ध स्थापित नहीं किया जा सकता
D) x ≥ y
E) x ≤ y
प्रश्न 18: प्रश्न में, दो समीकरण I और II दिए गए हैं। आपको x और y के बीच सही संबंध स्थापित करने और सही विकल्प चुनने के लिए दोनों समीकरणों को हल करना होगा।
I. x2 – x = 6
II. y2 + 7y + 10 = 0
A) x > y
B) x < y
C) x = y या सम्बन्ध स्थापित नहीं किया जा सकता
D) x ≥ y
E) x ≤ y
IBPS Clerk Prelims Free Mock Test
प्रश्न 19: प्रश्न में, दो समीकरण I और II दिए गए हैं। आपको x और y के बीच सही संबंध स्थापित करने और सही विकल्प चुनने के लिए दोनों समीकरणों को हल करना होगा।
I. x2 – 25 = 0
II. y3 = -216
A) x > y
B) x < y
C) x = y या सम्बन्ध स्थापित नहीं ककिया जा सकता
D) x ≥ y
E) x ≤ y
प्रश्न 20: प्रश्न में, दो समीकरण I और II दिए गए हैं। आपको x और y के बीच सही संबंध स्थापित करने और सही विकल्प चुनने के लिए दोनों समीकरणों को हल करना होगा।
I. x2 + 13x + 42 = 0
II. y2 + 15y + 56 = 0
A) x > y
B) x < y
C) x = y या सम्बन्ध स्थापित नहीं किया जा सकता
D) x ≥ y
E) x ≤ y
IBPS Clerk Prelims Free Mock Test
ANSWER KEYS and SOLUTIONS:
1) – D) | 2) – A) | 3) – E) | 4) – B) | 5) – A) | 6) – A) |
7) – C) | 8) – C) | 9) – B) | 10) – E) | 11) – B) | 12) – B) |
13) – A) | 14) – D) | 15) – A) | 16) – C) | 17) – B) | 18) – D) |
19) – A) | 20) – D) |
Solution 1: D)
The given series follows the following pattern:
11 + 9 = 20
20 + 11 = 31
31 + 13 = 44
44 + 15 = 59
59 + 17 = 76
Hence, option d.
Solution 2: A)
The given series follows the following pattern:
13 – 10 = 3
3 + 15 = 18
18 – 10 = 8
8 + 15 = 23
23 – 10 = 13
Hence, option a.
Solution 3: E)
The given series follows the following pattern: 6 × Consecutive prime numbers starting from 2.
6 × 2 = 12
6 × 3 = 18
6 × 5 = 30
6 × 7 = 42
6 × 11 = 66
6 × 13 = 78
Hence, option e.
Solution 4: B)
The given series follows the following pattern:
200 – 13 = 187
187 – 13 = 174
174 – 13 = 161
161 – 13 = 148
148 – 13 = 135
Hence, option b.
Solution 5: A)
The given series follows the following pattern:
3600 ÷ 6 = 600
600 ÷ 5 = 120
120 ÷ 4 = 30
30 ÷ 3 = 10
10 ÷ 2 = 5
Hence, option a.
Solution 6: A)
16% of 250 + 32% of 500 = ?
0.16 × 250 + 0.32 × 500 = ?
? = 40 + 160
? = 200
Hence, option a.
Solution 7: C)
? = 12 × 13 ÷ 3 + (2)3
? = 4 × 13 + 8
? = 52 + 8
? = 60
Hence, option c.
Solution 8: C)
25% of 120 + √225 + (2)2 = ?2
?2 = 30 + 15 + 4
?2 = 49
? = ±7
Hence, option c.
Solution 9: B)
3 × ?2 = 36 + 15 + 100 – 43
3 × ?2 = 51 + 57
?2 = 108 ÷ 3
?2 = 36
? = ±6
Hence, option b.
Solution 10: E)
28 + √144 + 144 ÷ (3)2 = ? – 4
28 + 12 + 144 ÷ 9 = ? – 4
? = 28 + 12 + 16 + 4
? = 60
Hence, option e.
Solution 11: B)
9.252 + (108.48 ÷ 3.89) = √? × 8.76
92 + (108 ÷ 4) ~ √? × 9
(81 + 27) ÷ 9 ~ √?
? ~122
? ~ 144 ~ 140
Hence, option b.
Solution 12: B)
14.992 – (299.78 ÷ 12.25) = ? × 4.89
152 – (300 ÷ 12) ~ ? × 5
225 – 25 ~ ? ×5
? ~ 200 ÷ 5
? ~ 40
Hence, option b.
Solution 13: A)
(7/12) × 179.89 + (15.34 × 4.89) = ?
(7/12) × 180 + (15 ×5) ~ ?
7 × 15 + 75 ~ ?
? ~ 105 + 75 ~ 180
Hence, option a.
Solution 14: D)
(√364 + 120.78) ÷ 6.78 = ? ÷ 3.88
(√361 + 121) ÷ 7 ~ ? ÷ 4
(19 + 121) ÷ 7 ~ ? ÷ 4
? ~ (140 ÷ 7) × 4
? ~ 80
Hence, option d.
Solution 15: A)
14.89% of 399.76 + (479.76 ÷ 12.34) = ?
15% of 400 + (480 ÷ 12) ~ ?
0.15 × 400 + 40 ~ ?
? ~ 60 + 40
? ~ 100
Hence, option a.
IBPS Clerk Prelims Free Mock Test
Solution 16: C)
From I:
x2 = 49
x = -7, 7
From II:
y2 + 8y = 0
y(y + 8) = 0
y = 0, -8
X | Relation | y |
-7 | < | 0 |
-7 | > | -8 |
7 | > | 0 |
7 | > | -8 |
So, the relationship between x and y cannot be established.
Hence, option c.
Solution 17: B)
From I:
x3 = -729
x = -9
From II:
y2 + 13y + 40 = 0
y2 + 8y + 5y + 40 = 0
y(y + 8) + 5(y + 8) = 0
(y + 8)(y + 5) = 0
y = -8, -5
X | Relation | y |
-9 | < | -8 |
-9 | < | -5 |
So, x < y
Hence, option b.
Solution 18: D)
From I:
x2 – x = 6
x2 – x – 6 = 0
x2 + 2x – 3x – 6 = 0
x(x + 2) – 3(x + 2) = 0
(x + 2)(x – 3) = 0
x = -2, 3
From II:
y2 + 7y + 10 = 0
y2 + 5y + 2y + 10 = 0
y(y + 5) + 2(y + 5) = 0
(y + 5)(y + 2) = 0
y = –5, -2
X | Relation | Y |
-2 | > | -5 |
-2 | = | -2 |
3 | > | -5 |
3 | > | -2 |
So, x ≥ y
Hence, option d.
Solution 19: A)
From I:
x2 – 25 = 0
x2 = 25
x = 5, -5
From II:
y3 = -216
y = -6
X | Relation | y |
5 | > | -6 |
-5 | > | -6 |
So, x > y
Hence, option a.
Solution 20: D)
From I:
x2 + 13x + 42 = 0
x2 + 7x + 6x + 42 = 0
x(x + 7) + 6(x + 7) = 0
(x + 7)(x + 6) = 0
x = -7, -6
From II:
y2 + 15y + 56 = 0
y2 + 8y + 7y + 56 = 0
y(y + 8) + 7(y + 8) = 0
(y + 8)(y + 7) = 0
y = -8, -7
X | Relation | Y |
-7 | > | -8 |
-7 | = | -7 |
-6 | > | -8 |
-6 | > | -7 |
So, x ≥ y
Hence, option d.
This brings us to the end of the article. Practice these important quant topics along with the given questions and solutions and check your exam preparation level. Sign up for more such important questions with solutions PDFs for banking exams.
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