IBPS Clerk Prelims Quant Scoring Topics with Practice Questions

IBPS Clerk prelims examination is to be held in the month of August/September and lately the last date of online registration has been extended till 28th July, 2023. For better preparation for IBPS Clerk Prelims exam it is important to go through all important and scoring topics thoroughly. Many people find quant as a difficult and lengthy section, but at the same time it is extremely scoring. So, for those who have difficulty in quant section and have discovered this blog have actually landed at the right place. Here we have got for you IBPS Clerk prelims quant scoring topics along with practice questions for those topics.

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IBPS Clerk Prelims Quant Scoring Topics

Some of the hot or you can scoring or important quant topics for IBPS Clerk prelims exam is mentioned below:

• Number Series
• Simplification
• Approximation
• Equation Comparison etc…

IBPS Clerk Prelims Quant Scoring Topics with Practice Questions

Number Series

Question 1: What will come in place of the question mark (?) in the following series?

11, 20, 31, 44, ?, 76

A) 63

B) 69

C) 45

D) 59

E) 49

Question 2: What will come in place of the question mark (?) in the following series?

13, 3, 18, 8, 23, ?

A) 13

B) 21

C) 28

D) 33

E) 3

Question 3: What will come in place of the question mark (?) in the following series?

12, 18, 30, 42, ?, 78

A) 52

B) 64

C) 72

D) 60

E) 66

Question 4: What will come in place of the question mark (?) in the following series?

200, 187, 174, ?, 148, 135

A) 158

B) 161

C) 151

D) 154

E) 164

Question 5: What will come in place of the question mark (?) in the following series?

3600, ?, 120, 30, 10, 5

A) 600

B) 300

C) 1200

D) 720

E) 240

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Simplification

Question 6: What will come in the place of question mark (?) in the given expression?

16% of 250 + 32% of 500 = ?

A) 200

B) 180

C) 160

D) 220

E) 175

Question 7: What will come in the place of question mark (?) in the given expression?

? = 12 × 13 ÷ 3 + (2)³

A) 55

B) 65

C) 60

D) 75

E) 70

Question 8: What will come in the place of question mark (?) in the given expression?

25% of 120 + √225 + (2)² = ?²

A) 8

B) 9

C) 7

D) 5

E) 6

Question 9: What will come in the place of question mark (?) in the given expression?

3 × ?² = 36 + 15 + 100 – 43

A) 8

B) 6

C) 7

D) 4

E) 2

Question 10: What will come in the place of question mark (?) in the given expression?

28 + √144 + 144 ÷ (3)² = ? – 4

A) 75

B) 64

C) 72

D) 80

E) 60

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Approximation

Question 11: What approximate value will come in place of the question mark (?) in the following question?(Note: You are not expected to calculate the exact value.)

9.25² + (108.48 ÷ 3.89) = √? × 8.76

A) 50

B) 140

C) 180

D) 80

E) 200

Question 12: What approximate value will come in place of the question mark (?) in the following question?(Note: You are not expected to calculate the exact value.)

14.99² – (299.78 ÷ 12.25) = ? × 4.89

A) 20

B) 40

C) 60

D) 90

E) 120

Question 13: What approximate value will come in place of the question mark (?) in the following question?(Note: You are not expected to calculate the exact value.)

(7/12) × 179.89 + (15.34 × 4.89) = ?

A) 180

B) 210

C) 150

D) 120

E) 240

Question 14: What approximate value will come in place of the question mark (?) in the following question?(Note: You are not expected to calculate the exact value.)

(√364 + 120.78) ÷ 6.78 = ? ÷ 3.88

A) 100

B) 40

C) 20

D) 80

E) 150

Question 15: What approximate value will come in place of the question mark (?) in the following question?(Note: You are not expected to calculate the exact value.)

14.89% of 399.76 + (479.76 ÷ 12.34) = ?

A) 100

B) 150

C) 120

D) 60

E) 160

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Equation Comparison

Question 16: In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y and choose the correct option.

I. x² = 49

II. y² + 8y = 0

A) x > y

B) x < y

C) x = y or the relationship cannot be established

D) x ≥ y

E) x ≤ y

Question 17: In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y and choose the correct option.

I. x³ = -729

II. y² + 13y + 40 = 0

A) x > y

B) x < y

C) x = y or the relationship cannot be established

D) x ≥ y

E) x ≤ y

Question 18: In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y and choose the correct option.

I. x² – x = 6

II. y² + 7y + 10 = 0

A) x > y

B) x < y

C) x = y or the relationship cannot be established

D) x ≥ y

E) x ≤ y

Question 19: In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y and choose the correct option.

I. x² – 25 = 0

II. y³ = -216

A) x > y

B) x < y

C) x = y or the relationship cannot be established

D) x ≥ y

E) x ≤ y

Question 20: In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y and choose the correct option.

I. x² + 13x + 42 = 0

II. y² + 15y + 56 = 0

A) x > y

B) x < y

C) x = y or the relationship cannot be established

D) x ≥ y

E) x ≤ y

प्रश्न 1: निम्नलिखित श्रृंखला में प्रश्नवाचक चिन्ह (?) के स्थान पर क्या आएगा?

11, 20, 31, 44, ?, 76

A) 63

B) 69

C) 45

D) 59

E) 49

प्रश्न 2: निम्नलिखित श्रृंखला में प्रश्नवाचक चिन्ह (?) के स्थान पर क्या आएगा?

13, 3, 18, 8, 23, ?

A) 13

B) 21

C) 28

D) 33

E) 3

प्रश्न 3: निम्नलिखित श्रृंखला में प्रश्नवाचक चिन्ह (?) के स्थान पर क्या आएगा?

12, 18, 30, 42, ?, 78

A) 52

B) 64

C) 72

D) 60

E) 66

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प्रश्न 4: निम्नलिखित श्रृंखला में प्रश्नवाचक चिन्ह (?) के स्थान पर क्या आएगा?

200, 187, 174, ?, 148, 135

A) 158

B) 161

C) 151

D) 154

E) 164

प्रश्न 5: निम्नलिखित श्रृंखला में प्रश्नवाचक चिन्ह (?) के स्थान पर क्या आएगा?

3600, ?, 120, 30, 10, 5

A) 600

B) 300

C) 1200

D) 720

E) 240

प्रश्न 6: दिए गए समीकरण में प्रश्नवाचक चिन्ह (?) के स्थान पर क्या आएगा?

16% of 250 + 32% of 500 = ?

A) 200

B) 180

C) 160

D) 220

E) 175

प्रश्न 7: दिए गए समीकरण में प्रश्नवाचक चिन्ह (?) के स्थान पर क्या आएगा?

? = 12 × 13 ÷ 3 + (2)³

A) 55

B) 65

C) 60

D) 75

E) 70

प्रश्न 8: दिए गए समीकरण में प्रश्नवाचक चिन्ह (?) के स्थान पर क्या आएगा?

25% of 120 + √225 + (2)² = ?²

A) 8

B) 9

C) 7

D) 5

E) 6

प्रश्न 9: दिए गए समीकरण में प्रश्नवाचक चिन्ह (?) के स्थान पर क्या आएगा?

3 × ?² = 36 + 15 + 100 – 43

A) 8

B) 6

C) 7

D) 4

E) 2

प्रश्न 10: दिए गए समीकरण में प्रश्नवाचक चिन्ह (?) के स्थान पर क्या आएगा?

28 + √144 + 144 ÷ (3)² = ? – 4

A) 75

B) 64

C) 72

D) 80

E) 60

प्रश्न 11: निम्नलिखित प्रश्न में प्रश्न चिह्न (?) के स्थान पर क्या अनुमानित मान आएगा? (नोट: आपको सटीक मान की गणना करने की आवश्यकता नहीं है।)

9.25² + (108.48 ÷ 3.89) = √? × 8.76

A) 50

B) 140

C) 180

D) 80

E) 200

प्रश्न 12: निम्नलिखित प्रश्न में प्रश्न चिह्न (?) के स्थान पर क्या अनुमानित मान आएगा? (नोट: आपको सटीक मान की गणना करने की आवश्यकता नहीं है।)

14.99² – (299.78 ÷ 12.25) = ? × 4.89

A) 20

B) 40

C) 60

D) 90

E) 120

प्रश्न 13: निम्नलिखित प्रश्न में प्रश्न चिह्न (?) के स्थान पर क्या अनुमानित मान आएगा? (नोट: आपको सटीक मान की गणना करने की आवश्यकता नहीं है।)

(7/12) × 179.89 + (15.34 × 4.89) = ?

A) 180

B) 210

C) 150

D) 120

E) 240

प्रश्न 14: निम्नलिखित प्रश्न में प्रश्न चिह्न (?) के स्थान पर क्या अनुमानित मान आएगा? (नोट: आपको सटीक मान की गणना करने की आवश्यकता नहीं है।)

(√364 + 120.78) ÷ 6.78 = ? ÷ 3.88

A) 100

B) 40

C) 20

D) 80

E) 150

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प्रश्न 15: निम्नलिखित प्रश्न में प्रश्न चिह्न (?) के स्थान पर क्या अनुमानित मान आएगा? (नोट: आपको सटीक मान की गणना करने की आवश्यकता नहीं है।)

14.89% of 399.76 + (479.76 ÷ 12.34) = ?

A) 100

B) 150

C) 120

D) 60

E) 160

प्रश्न 16: प्रश्न में, दो समीकरण I और II दिए गए हैं। आपको x और y के बीच सही संबंध स्थापित करने और सही विकल्प चुनने के लिए दोनों समीकरणों को हल करना होगा।

I. x² = 49

II. y² + 8y = 0

A) x > y

B) x < y

C) x = y या सम्बस्न्ध स्थापित नहीं किया जा सकता

D) x ≥ y

E) x ≤ y

प्रश्न 17: प्रश्न में, दो समीकरण I और II दिए गए हैं। आपको x और y के बीच सही संबंध स्थापित करने और सही विकल्प चुनने के लिए दोनों समीकरणों को हल करना होगा।

I. x³ = -729

II. y² + 13y + 40 = 0

A) x > y

B) x < y

C) x = y या सम्बन्ध स्थापित नहीं किया जा सकता

D) x ≥ y

E) x ≤ y

प्रश्न 18: प्रश्न में, दो समीकरण I और II दिए गए हैं। आपको x और y के बीच सही संबंध स्थापित करने और सही विकल्प चुनने के लिए दोनों समीकरणों को हल करना होगा।

I. x² – x = 6

II. y² + 7y + 10 = 0

A) x > y

B) x < y

C) x = y या सम्बन्ध स्थापित नहीं किया जा सकता

D) x ≥ y

E) x ≤ y

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प्रश्न 19: प्रश्न में, दो समीकरण I और II दिए गए हैं। आपको x और y के बीच सही संबंध स्थापित करने और सही विकल्प चुनने के लिए दोनों समीकरणों को हल करना होगा।

I. x² – 25 = 0

II. y³ = -216

A) x > y

B) x < y

C) x = y या सम्बन्ध स्थापित नहीं ककिया जा सकता

D) x ≥ y

E) x ≤ y

प्रश्न 20: प्रश्न में, दो समीकरण I और II दिए गए हैं। आपको x और y के बीच सही संबंध स्थापित करने और सही विकल्प चुनने के लिए दोनों समीकरणों को हल करना होगा।

I. x² + 13x + 42 = 0

II. y² + 15y + 56 = 0

A) x > y

B) x < y

C) x = y या सम्बन्ध स्थापित नहीं किया जा सकता

D) x ≥ y

E) x ≤ y

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ANSWER KEYS and SOLUTIONS:

Solution 1: D)

The given series follows the following pattern:

11 + 9 = 20

20 + 11 = 31

31 + 13 = 44

44 + 15 = 59

59 + 17 = 76

Hence, option d.

Solution 2: A)

The given series follows the following pattern:

13 – 10 = 3

3 + 15 = 18

18 – 10 = 8

8 + 15 = 23

23 – 10 = 13

Hence, option a.

Solution 3: E)

The given series follows the following pattern: 6 × Consecutive prime numbers starting from 2.

6 × 2 = 12

6 × 3 = 18

6 × 5 = 30

6 × 7 = 42

6 × 11 = 66

6 × 13 = 78

Hence, option e.

Solution 4: B)

The given series follows the following pattern:

200 – 13 = 187

187 – 13 = 174

174 – 13 = 161

161 – 13 = 148

148 – 13 = 135

Hence, option b.

Solution 5: A)

The given series follows the following pattern:

3600 ÷ 6 = 600

600 ÷ 5 = 120

120 ÷ 4 = 30

30 ÷ 3 = 10

10 ÷ 2 = 5

Hence, option a.

Solution 6: A)

16% of 250 + 32% of 500 = ?

0.16 × 250 + 0.32 × 500 = ?

? = 40 + 160

? = 200

Hence, option a.

Solution 7: C)

? = 12 × 13 ÷ 3 + (2)³

? = 4 × 13 + 8

? = 52 + 8

? = 60

Hence, option c.

Solution 8: C)

25% of 120 + √225 + (2)² = ?²

?² = 30 + 15 + 4

?² = 49

? = ±7

Hence, option c.

Solution 9: B)

3 × ?² = 36 + 15 + 100 – 43

3 × ?² = 51 + 57

?² = 108 ÷ 3

?² = 36

? = ±6

Hence, option b.

Solution 10: E)

28 + √144 + 144 ÷ (3)² = ? – 4

28 + 12 + 144 ÷ 9 = ? – 4

? = 28 + 12 + 16 + 4

? = 60

Hence, option e.

Solution 11: B)

9.25² + (108.48 ÷ 3.89) = √? × 8.76

9² + (108 ÷ 4) ~ √? × 9

(81 + 27) ÷ 9 ~ √?

? ~12²

? ~ 144 ~ 140

Hence, option b.

Solution 12: B)

14.99² – (299.78 ÷ 12.25) = ? × 4.89

15² – (300 ÷ 12) ~ ? × 5

225 – 25 ~ ? ×5

? ~ 200 ÷ 5

? ~ 40

Hence, option b.

Solution 13: A)

(7/12) × 179.89 + (15.34 × 4.89) = ?

(7/12) × 180 + (15 ×5) ~ ?

7 × 15 + 75 ~ ?

? ~ 105 + 75 ~ 180

Hence, option a.

Solution 14: D)

(√364 + 120.78) ÷ 6.78 = ? ÷ 3.88

(√361 + 121) ÷ 7 ~ ? ÷ 4

(19 + 121) ÷ 7 ~ ? ÷ 4

? ~ (140 ÷ 7) × 4

? ~ 80

Hence, option d.

Solution 15: A)

14.89% of 399.76 + (479.76 ÷ 12.34) = ?

15% of 400 + (480 ÷ 12) ~ ?

0.15 × 400 + 40 ~ ?

? ~ 60 + 40

? ~ 100

Hence, option a.

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Solution 16: C)

From I:

x² = 49

x = -7, 7

From II:

y² + 8y = 0

y(y + 8) = 0

y = 0, -8

So, the relationship between x and y cannot be established.

Hence, option c.

Solution 17: B)

From I:

x³ = -729

x = -9

From II:

y² + 13y + 40 = 0

y² + 8y + 5y + 40 = 0

y(y + 8) + 5(y + 8) = 0

(y + 8)(y + 5) = 0

y = -8, -5

So, x < y

Hence, option b.

Solution 18: D)

From I:

x² – x = 6

x² – x – 6 = 0

x² + 2x – 3x – 6 = 0

x(x + 2) – 3(x + 2) = 0

(x + 2)(x – 3) = 0

x = -2, 3

From II:

y² + 7y + 10 = 0

y² + 5y + 2y + 10 = 0

y(y + 5) + 2(y + 5) = 0

(y + 5)(y + 2) = 0

y = –5, -2

So, x ≥ y

Hence, option d.

Solution 19: A)

From I:

x² – 25 = 0

x² = 25

x = 5, -5

From II:

y³ = -216

y = -6

So, x > y

Hence, option a.

Solution 20: D)

From I:

x² + 13x + 42 = 0

x² + 7x + 6x + 42 = 0

x(x + 7) + 6(x + 7) = 0

(x + 7)(x + 6) = 0

x = -7, -6

From II:

y² + 15y + 56 = 0

y² + 8y + 7y + 56 = 0

y(y + 8) + 7(y + 8) = 0

(y + 8)(y + 7) = 0

y = -8, -7

So, x ≥ y

Hence, option d.

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