High level DI for SBI PO

High level DI for SBI PO: The preparation for data interpretation for SBI PO exam is a must, especially from the perspective of mains. A separate section is dedicated just for DI in SBI PO mains. If you have been looking for high level DI for SBI PO questions, then you have arrived at the right place. You will get exposed to different type of DI-based questions today. With answer key it will also help you in arriving at the right conclusion in terms of your approach. Analyse your approach based on the answer key.

High level DI for SBI PO Questions & Answers

Caselet DI:

4000 people (male + female) participated in an event and categorised in three different categories i.e. VVIP, VIP and normal people. Ratio of VIPs to VVIPs who participated in the event is 7:5. Out of total normal people who participated in the event, 40% were males which were 512 less than number of male VIPs who participated in the event. Out of total VVIPs who participated in the event, 450 were males, while the sum of number of female VIPs and VVIPs together who participated in the event was 1470. 

Common Solution: 

Let the number of VIPs and VVIPs who participated in the event be 7x and 5x, respectively 

Therefore, number of normal people who participated in the event = 4000 – (7x + 5x) = (4000 – 12x) 

Number of normal males who participated in the event = 0.4(4000 – 12x) = (1600 – 4.8x) 

Number of normal females who participated in the event = 0.6(4000 – 12x) = (2400 – 7.2x) 

Number of male VIPs who participated in the event = 1600 – 4.8x + 512 = (2112 – 4.8x) 

Number of female VIPs who participated in the event = 7x – (2112 – 4.8x) = (11.8x – 2112)  

Number of male VVIPs who participated in the event = 450 

Number of female VVIPs who participated in the event = (5x – 450) 

According to the question, 

11.8x – 2112 + 5x – 450 = 1470 

Or, 16.8x = 4032 

Or, x = 240 

Therefore, number of normal people who participated in the event = (4000 – 12x) = 1120 

Number of normal males who participated in the event = 0.4 ×1120 = 448 

Number of normal females who participated in the event = 1120 – 448 = 672 

Number of VIPs who participated in the event = 7x = 1680 

Number of male VIPs who participated in the event = 448 + 512 = 960 

Number of female VIPs who participated in the event = 1680 – 960 = 720 

Number of VVIPs who participated in the event = 5x = 1200 

Number of male VVIPs who participated in the event = 450 

Number of female VVIPs who participated in the event = 1200 – 450 = 750 

1.) Find the sum of the number of normal females and female VIPs who participated in the event. 

a.) 1382 

b.) 1424 

c.) 1248 

d.) 1392 

e.) 1164 

Answer: d) 

Solution: 

Required sum = 672 + 720 = 1392 

Hence, option d. 

Mixed Chart DI:

The given pie-chart shows the percentage distribution of total number of five different types of energy drinks sold on Monday and Friday together. The number of bottles of Amp sold on Monday and Friday together is 360 more than the number of bottles of Nos sold on Monday and Friday together. 

The given line graph shows the percentage of number of bottles of each energy drink sold on Monday out of the total number of bottles of that drink sold on Monday and Friday together. 

Common Solution: 

Let the total number of bottles of given five energy drinks sold on Monday and Friday together be ‘x’ 

Therefore, number of bottles of Nos sold on Monday and Friday together = 0.18x 

Number of bottles of Amp sold on Monday and Friday together = 0.26x 

According to the question, 

0.26x – 0.18x = 360 

Or, 0.08x = 360 

Or, x = 360/0.08 = 4500 

Therefore, 

Number of bottles of Red bull sold on Monday and Friday together = 0.12x = 540 

Number of bottles of Red bull sold on Monday = 0.25 × 540 = 135 

Number of bottles of Red bull sold on Friday = 540 – 135 = 405 

Similarly, 

Energy drink	Total bottles sold	Number of bottles sold on Monday	Number of bottles sold on Friday
Red bull	540	135	405
Monster	900	360	540
Nos	810	162	648
Bang	1080	648	432
Amp	1170	351	819

1.) Number of bottles of Bang sold on Friday is how much percent more/less than the number of bottles of Monster sold on Monday? 

a.) 12% 

b.) 30% 

c.) 15% 

d.) 20% 

e.) 25% 

Answer: d) 

Solution: 

Required percentage = {(432 – 360)/360} × 100 = 20% 

Hence, option d. 

High level DI for SBI PO – Missing DI

The table given below shows the number of smart bulbs manufactured by five different companies in 2017. It also shows the percentage of these smart bulbs sold, price of each bulb and total revenue generated by the sale of these bulbs by each company. 

Company	Number of bulbs manufactured	Percentage of bulbs sold	Price of a bulb (Rs.)	Revenue generated (Rs.)
Philips	1250	–	75	56,250
MI	–	75%	120	75,600
Bajaj	750	80%	80	–
Surya	1240	–	60	33,480
Orient	1500	40%	–	75,000

Common Solution: 

Company	Number of bulbs manufactured	Number of bulbs sold	Number of unsold bulbs	Price of a bulb (Rs.)	Revenue generated (Rs.)
Philips	1250	56250/75 = 750	1250 – 750 = 500	75	56,250
MI	630/0.75 = 840	75600/120 = 630	840 – 630 = 210	120	75,600
Bajaj	750	0.80 × 750 = 600	750 – 600 = 150	80	80 × 600 = 48,000
Surya	1240	33480/60 = 558	1240 – 558 = 682	60	33,480
Orient	1500	0.40 × 1500 = 600	1500 – 600 = 900	75000/600 = 125	75,000

1.) What is the difference between the total revenue generated by Bajaj and that by Surya by selling smart bulbs in 2017? 

a.) Rs. 15,120 

b.) Rs. 11,300 

c.) Rs. 14,520 

d.) Rs. 15,280 

e.) Rs. 12,340 

Answer: c) 

Solution: 

Desired difference = 48000 – 33480 = Rs. 14,520 

Hence, option c. 

Pie Chart DI

The pie chart given below shows the percentage distribution of the number of B-schools which got different ratings i.e. (5, 4, 3, 2 and 1) out of 5 in terms of placement criteria. The average number of professors in each B-school with grade 2 is 17, while the total number of professors in all the B-schools with grade 2 is 3468. 

Common Solution: 

Number of B-schools which received grade 2 = 3468/17 = 204 

Total number of B-schools together = (204/17) × 100 = 1200 

Grade	Number of B-schools
5	9 × 12 = 108
4	15 × 12 = 180
3	23 × 12 = 276
2	17 × 12 = 204
1	36 × 12 = 432

Topic: Pie chart 

Sub topic: Normal 

Lvl: 1 

Q1. Average number of students per B-school with grade 4 is 84. If the ratio of the total number of boys to girls in all the B-schools with grade 4 is 11: 9, then find the total number of girls in all the B-schools together with grade 4. 

a) 6804 

b) 7210 

c) 6640 

d) 6274 

e) None of these 

Ans: a 

Solution: 

Total number of students = 180 × 84 = 15120 

Required number of girls = 9/20 × 15120 = 6804 

Hence, option a.  

Arithmetic Based DI

The line graph given below shows the percentage by which five different friends marked their goods above the cost price, and the discount percentage given and the amount (in Rs.) for which they sold their articles. 

Common Solution: 

For Carryminati: 

Let cost price of the article = Rs. 100x 

Marked price of the article = 1.6 × 100x = Rs. 160x 

Selling price of the article = 0.6 × 160x = 96x 

So, 96x = 768  

x = 8 

Cost price of the article = Rs. 800 

Marked price of the article = 160 × 8 = Rs. 1280  

For Bhuvan: 

Let cost price of the article = Rs. 100x 

Marked price of the article = 1.5 × 100x = Rs. 150x 

Selling price of the article = 0.64 × 150x = 96x 

So, 96x = 864  

x = 9 

Cost price of the article = Rs. 900 

Marked price of the article = 150 × 9 = Rs. 1350  

For Amit: 

Let cost price of the article = Rs. 100x 

Marked price of the article = 1.75 × 100x = Rs. 175x 

Selling price of the article = 0.72 × 175x = 126x 

So, 126x = 756  

x = 6 

Cost price of the article = Rs. 600 

Marked price of the article = 175 × 6 = Rs. 1050  

For Ashish: 

Let cost price of the article = Rs. 100x 

Marked price of the article = 1.65 × 100x = Rs. 165x 

Selling price of the article = 0.68 × 165x = 112.2x 

So, 112.2x = 1122 

x = 10 

Cost price of the article = Rs. 1000 

Marked price of the article = 165 × 10 = Rs. 1650  

For Harsh: 

Let cost price of the article = Rs. 100x 

Marked price of the article = 1.8 × 100x = Rs. 180x 

Selling price of the article = 0.72 × 180x = 129.6x 

So, 129.6x = 648  

x = 5 

Cost price of the article = Rs. 500 

Marked price of the article = 180 × 5 = Rs. 900  

Names	Marked price (in Rs.)	Cost price (in Rs.)
Carryminati	1280	800
Bhuvan	1350	900
Amit	1050	600
Ashish	1650	1000
Harsh	900	500

1. What is the cost price of article for Carryminati?     

a.) Rs. 600 

b.) Rs. 800 

c.) Rs. 850 

d.) Rs. 900 

e.) None of these 

Ans: b 

Solution: 

Cost price of article for Carryminati = Rs. 800 

Hence, option b. 

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