EPFO Steno Reasoning Ability/General Aptitude Free Preparation Questions

The Employees’ Provident Fund Organisation (EPFO) will soon release the EPFO Stenographer 2023 exam dates. EPFO Steno’s recruitment notification has already been released, however the exam dates have not been announced yet. For candidates those who have not started their exam preparation it is important for the candidates to be familiarized with the EPFO Stenographer exam pattern and syllabus. EPFO Steno has Reasoning Ability/General Aptitude as a section and in this article we will be discussing the EPFO steno syllabus and along with this we are going to provide few EPFO Steno Reasoning Ability/General Aptitude Free Preparation Questions. These free questions will be like practice questions along with the answers. 

EPFO Steno 2023 Exam Pattern

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EPFO Steno 2023 Syllabus

EPFO Steno Reasoning Ability/General Aptitude Free Preparation Questions

Topic: SSC Syllogisms

Subtopic: Statements and Conclusions

Level: 0

1.) In the question below some statements are given followed by three conclusions I, II and III. You have to take the given statements to be true even if they seem to be at variance with commonly known facts. Read all the conclusions and then decide which of the given conclusion definitely follows from the given statements, disregarding commonly known facts.

Statements:

All Tire is Rubber.

No Rubber is Iron.

All Iron is Steel.

Conclusions:

I. Some Tire is not Iron.

II. Some Rubber is Tire.

III. Some Steel is not Iron.

a.) Only conclusion I follows

b.) Only conclusions I and II follow

c.) Only conclusion III follows

d.) Only conclusion II follows

Answer: b)

Solution:

Following figure can be formed:

From the above figure, only conclusions I and II follow.

Hence, option b.

Topic: SSC Analogy

Subtopic: Words

Level: 0

2.) Select the option that is related to the third term in the same way as the second term is related to first term.

STRUGGLE: DMFHTSST :: HARMONY: ?

a.) XONNQBG

b.) XSNNQBG

c.) XONNPBG

d.) XONNQCG

Answer: a)

Solution:

The letters in the word are written in reverse order. Then immediate preceding and immediate succeeding letters are written for the alternate letters as per the English Alphabetical series.

As, ‘STRUGGLE’ is coded as ‘DMFHTSST’

Similarly, ‘HARMONY’ is coded as ‘XONNQBG’

Hence, option a.

Topic: SSC Analogy

Subtopic: Words

Level: 0

3.) Select the option that is related to the third word in the same way as the second word is related to first word.

Gravity: Pull :: Magnetism: ?

a.) Earth

b.) Attract

c.) Throw

d.) Wire

Answer: b)

Solution: As, Gravity pulls the mass.

Similarly,

Magnetism attracts the metallic objects.

Hence, option b.

Topic: SSC Classification

Subtopic: Words

Level: 0

4.) Four letter- clusters have been given out of which three are alike in some manner, while one is different. Choose the odd one.

a.) DNMDEA

b.) TSDREE

c.) FNNLAE

d.) RMNIELA

Answer: c)

Solution:

On rearranging the letters in each option, we get an English Meaningful word.

From option (a): DNMDEA – DEMAND

From option (b): TSDREE – DESERT

From option (c): FNNLAE – No English Meaningful word can be formed.

From option (d): RMNIELA- MINERAL

Hence, option c.

EPFO Steno 2023 Free Mock Test

Topic: SSC Non – Verbal Reasoning

Subtopic: Embedded

Level: 0

5.) Select the option in which the given figure is embedded (Rotation is not allowed).

a.)

b.) 

c.) 

d.) 

Answer: d)

Solution:

The embedded figure is shown below:

Hence, option d.

EPFO Steno 2023 Free Mock Test

Topic: SSC Coding Decoding

Subtopic: Words

Level: 0

6.) In a certain code language, ‘Q’ is coded as ’25.5’ and ‘L’ is coded as ‘18’ then ‘TEN’ will be coded as ____ in the same code language.

a.) 25, 7.5, 14

b.) 45, 14, 14

c.) 30, 7.5, 21

d.) 15, 14, 21

Answer: c)

Solution:

The letters are coded as:

The positional value of the alphabet is multiplied by 1.5 to obtain the code.

The positional value of ‘Q’ is 17, so Q is coded as (17 × 1.5) = 25.5.

The positional value of ‘L’ is 12, so L is coded as (12 × 1.5) = 18.

Similarly,

The positional value of ‘T’ is 20, so T is coded as (20 × 1.5) = 30.

The positional value of ‘E’ is 05, so E is coded as (5 × 1.5) = 7.5.

The positional value of ‘N’ is 14, so N is coded as (14 × 1.5) = 21.

Therefore, the code of “TEN” is: (30, 7.5, 21)

Hence, option c.

EPFO Steno 2023 Free Mock Test

Topic: SSC Venn Diagram

Subtopic: Logic

Level: 0

7.) Which Venn diagram represents the correct relationship between:

Clock, Time, Watch

a.)

b.)

c.)

d.)

Answer: b)

Both Clock and Watch are devices, which show time.

Hence, option b.

EPFO Steno 2023 Free Mock Test

Topic: SSC Miscellaneous

Subtopic: Matrix

Level: 0

8.) What will come in the place of question mark?

a.) Q

b.) D

c.) G

d.) N

Answer: a)

Solution:

In each row,

2^nd letter is immediate succeeding vowel after the 1^st letter. 3^rd letter is opposite of the 2^nd letter as per the English Alphabetical Series.

In row 1,

1^st letter = K, 2^nd letter = O (immediate succeeding vowel after K), 3^rd letter = L (opposite letter of O)

In row 2,

1^st letter = C, 2^nd letter = E (immediate succeeding vowel after C), 3^rd letter = V (opposite letter of E)

Similarly,

In row 3,

2^nd letter = U, so, the 1^st letter should be a consonant which comes before U and after O.

From the given options, we can say, Q can be the 1^st letter.

1^st letter = Q, 2^nd letter = U (immediate succeeding vowel after Q), 3^rd letter = F (opposite letter of U)

Hence, option a.

EPFO Steno 2023 Free Mock Test

Topic: SSC Blood Relations

Subtopic: Normal

Level: 0

9.) Pointing to a picture, Mina said, “He is son of my husband’s only daughter’s brother in law’s only brother”. How is the person in the picture related to Mina?

a.) Grandson

b.) Grandmother

c.) Son

d.) Cannot be determined

Answer: a)

Solution:

We make the following family tree:

Person in the picture is Grandson of Mina.

Hence, option a.

EPFO Steno 2023 Free Mock Test

Topic: SSC Puzzles

Subtopic: Floor

Level: 0

10.) Five persons A, B, C, D and E live on different floors of a five-storey building. D lives two floors above C. One person lives between D and E. B doesn’t live immediately below D. Who lives two floors above A?

a.) B

b.) D

c.) C

d.) E

Answer: a)

Solution:

Clues:

1. D lives two floors above C.

2. One person lives between D and E.

3. B doesn’t live immediately below D.

Inference:

From Clue 1 and 2, we get C lives on 1^st floor, D lives on 3^rd floor, E lives on 5^th floor.

From Clue 3, we get B lives on 4^th floor and A lives on 2^nd floor.

Therefore, the final arrangement is given below:

So, B lives two floors above A.

Hence, option a.

EPFO Steno 2023 Free Mock Test

This brings us to the end of the article. Practice this set of reasoning questions and stay ahead in your exam preparation. 

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