Boost Arithmetic Speed & Accuracy for RBI Grade B Exam

Arithmetic is a major scoring area in the RBI Grade B Phase 1 exam. This part of the exam requires strong calculation skills and quick thinking. So, this requirement makes it necessary to accelerate your math speed and accuracy. By improving these skills, you can improve your scoring potential in the exam, especially since this section is bound by time and has a high weightage. In this blog, we’ll provide you with some important sample questions for practice and also discuss top practical tips and techniques that will help you increase your arithmetic speed and accuracy for the RBI Grade B exam.

Types of Arithmetic Questions in RBI Grade B Exam

The arithmetic section in RBI Grade B includes various types of questions. These questions test candidates’ ability to perform calculations efficiently. Here are the common types of questions you can expect:

• Percentage Problems: These questions test your ability to solve problems related to percentages, profit and loss, discounts, etc.
• Ratio and Proportion: Questions in this category focus on solving problems based on ratios, proportions, and mixtures.
• Time and Work: These questions deal with the concepts of work efficiency and the time required to complete a task.
• Speed, Distance, and Time: This involves calculating speed, distance, and time for different moving objects.
• Ages and Mixtures: You may be asked to solve problems related to the ages of people or mixtures of substances.
• Simple and Compound Interest: These questions will test your understanding of financial mathematics, including the calculation of interest over time.

Tips to Boost Arithmetic Speed and Accuracy for RBI Grade B Exam

It is vital to improve the speed and accuracy of solving srithmetic based questions, as the RBI Grade B exam is time-bound. Here are some effective tips to help you achieve that:

1. Master the Basics

Make sure you have a clear understanding of fundamental arithmetic concepts. If you’ll not work on solidifying your foundation, it will become tough to solve complicated problems quickly. So, you need to focus on topics like percentages, ratios, time and work, and profit and loss.

2. Practice Regularly

The more you practice, the faster you’ll get. Start solving basic problems. And then move to more difficult ones. You should try you bst to solve a multitude of arithmetic problems every day to build your speed.

3. Learn Shortcuts and Tricks

There are many shortcuts in arithmetic that can save you time. For example, learning tricks to solve percentage and ratio-based problems quickly can help you save valuable seconds during the exam.

4. Improve Mental Calculation Skills

You should also reduce your reliance on a calculator as the exam has time limits. Try to practice solving problems mentally. It will help you calculate and solve questions faster in the real exam.

5. Solve Questions Under Time Pressure

Solve arithmetic questions within a limited time frame to get aclimatize your brain to the real exam conditions. This will help you get used to the pressure and improve your time management skills.

6. Use Approximation When Possible

For complicated calculations, use approximations to save time. Master Estimating answers. It can help you quickly eliminate incorrect options and reach the correct solution faster.

Sample Questions for Practice

Given below are sample questions that you can solve by applying the tips you learnt above. When you regularly practice and apply these tips, you can greatly improve your arithmetic speed and accuracy. And after just a few weeks of consistent effort, you will be well-prepared to face all types of Arithmetic questions in the RBI Grade B exam confidently.

Question 1: A bag contains ‘x’ black balls, ‘x + 2’ red balls and ‘x + 8’ white balls. The probability of drawing a white ball is 3/20 more than the probability of drawing a red ball. If two balls are randomly drawn from the bag, then what is the probability that one ball is red and other is black?

A) 2/13

B) 4/9

C) 1/7

D) 5/17

E) 3/14

Question 2: A bag contains ‘x’ blue, ‘x + 3’ pink and ‘2x – 3’ black balls. Two balls are randomly drawn from the bag such that both the balls are of same colour. Find the total number of balls in the bag if the number of ways in which two balls of same colour can be drawn is 121.

A) 20

B) 24

C) 28

D) 32

E) None of these

Question 3: ‘X’ can do a piece of work in 12 hours while ‘Y’ can do the same work in 18 hours. If ‘X’ starts working at 12:00 and ‘Y’ joins him at ___, then the whole work will be completed this way in __ hours.

The values given in which of the following options will fill the blanks in the same order in which is it given to make the statement true:

I. 16:00, 4.8 hours

II. 18:00, 9.6 hours

III. 14:00, 8 hours

A) Only I

B) Only I and II

C) All I, II and III

D) Only II and III

E) Only III

Question 4: The speed of a boat in still water is 19 km/h. If the time taken by the boat to travel ‘x’ km in upstream is 5 hours more than time taken by it to travel ‘x’ km in downstream, then find the time taken by the boat to cover ‘2x’ km in upstream such that the speed of the stream now is 40% less than the speed of stream originally.

A) 20 hours

B) 18 hours

C) 24 hours

D) 16 hours

E) Cannot be determined.

Question 5: A person invested Rs. ‘x’ in scheme ‘A’ offering compound interest of 24% p.a., compounded annually and received Rs. 19220 after 2 years. He again invested Rs. (y – x) in scheme ‘B’ offering compound interest of 20% p.a. compounded annually and received Rs. (x + 1324) after 3 years. Find the value of ‘y’.

A) 22500

B) 19500

C) 21000

D) 19824

E) 20500

ANSWER KEYS and SOLUTIONS:

1) – A)

2) – C)

3) – D)

4) – E)

5) – E)

Solution 1: A)

According to question:

(x + 8)/(3x + 10) – (x + 2)/(3x + 10) = 3/20

6/(3x + 10) = 3/20

9x + 30 = 120

9x = 90

x = 10

So, there are 10 black, 12 red and 18 white balls in the bag.

Required probability = (¹²C₁ × ¹⁰C₁)/⁴⁰C₂ = (12 × 10)/780 = 2/13

Hence, option a.

Solution 2: C)

According to question:

^xC₂ + ^x+3C₂ + ^2x-3C₂ = 121

{x(x – 1)/2} + {(x + 3)(x + 2)/2} + {(2x – 3)(2x – 4)/2} = 121

x² – x + x² + 5x + 6 + 4x² –14x + 12 = 242

6x² – 10x – 224 = 0

3x² – 5x – 112 = 0

3x² – 21x + 16x – 112 = 0

3x(x – 7) + 16(x – 7) = 0

(3x + 16)(x – 7) = 0

x = 7, -16/3

Number of balls can’t be negative, so ‘x’ = 7

Total number of balls in the bag = 7 + 10 + 11 = 28

Hence, option c.

Solution 3: D)

Let the total work = 36 units {LCM (12 and 18)}

Per hour efficiency of ‘X’ = 36/12 = 3 units

Per hour efficiency of ‘Y’ = 36/18 = 2 units

For I:

Time for which ‘X’ worked alone = 16 – 12 = 4 hours

Work done by ‘X’ in 4 hours = 4 × 3 = 12 units

Remaining work = 36 – 12 = 24 units

Time taken by ‘A’ and ‘B’ together to do the remaining work = 24/5 = 4.8 hours

Total time taken = 4 + 4.8 = 8.8 hours ≠ 4.8 hours

Therefore, I is false.

For II:

Time for which ‘X’ worked alone = 18 – 12 = 6 hours

Work done by ‘X’ in 6 hours = 6 × 3 = 18 units

Remaining work = 36 – 18 = 18 units

Time taken by ‘A’ and ‘B’ together to do the remaining work = 18/5 = 3.6 hours

Total time taken = 3.6 + 6 = 9.6 hours = 9.6 hours

Therefore, II is true.

For III:

Time for which ‘X’ worked alone = 14 – 12 = 2 hours

Work done by ‘X’ in 2 hours = 2 × 3 = 6 units

Remaining work = 36 – 6 = 30 units

Time taken by ‘A’ and ‘B’ together to do the remaining work = 30/5 = 6 hours

Total time taken = 2 + 6 = 8 hours = 8 hours

Therefore, III is true.

Hence, option d.

Solution 4: E)

According to the question,

Distance travelled by the boat in upstream = distance travelled by the boat in downstream = ‘x’ km

Let the time taken for the boat to travel ‘x’ km downstream = t hours

Then, time taken by the boat to travel ‘x’ km upstream = (t + 5) hours

We know that speed = distance ÷ time

Let the speed of the stream = y km/h

Then,

x = (19 – y) × (t + 5) = (19 + y) × (t)

Or, 19t – yt + 95 – 5y = 19t + yt

Or, 95 – 5y = 2yt

This equation cannot be solved further to obtain the value of ‘y’ or ‘t’.

Hence, the answer cannot be calculated.

Hence, option e.

Solution 5: E)

ATQ;

x{1 + (24/100)}² = 19220

Or, (961x/ 625) = 19220

Or, x = (19220 ÷ 961) × 625 = 12500

And, (y – x){1 + (20/100)}³ = 12500 + 1324 = 13824

Or, 216(y – x)/125 = 13824

Or, y – x = (13824 ÷ 216) × 125 = 8000

y = 12500 + 8000 = 20500

Hence, option e.

Takeaway

Improving your arithmetic speed and accuracy is essential for performing well in the RBI Grade B exam. Start practicing today and use these tips to increase your chances of success. Don’t forget to take our FREE RBI Grade B Phase 1 Mock Test to begin your preparation journey with confidence!

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