Average For IBPS RRB Exam 2025, Check Practical Questions

Average for IBPS RRB Exam 2025: The topic of Averages is an important part of the Quantitative Aptitude section in the IBPS RRB 2025 Exam. Mastering the concept of averages not only helps in scoring well in standalone questions but also strengthens your foundation for Data Interpretation (DI) sets. In this article, we provide a clear overview of the average concept along with practical questions and tricks to enhance your speed and accuracy. Candidates can check practice questions in the article below.

Practical Questions For Average

Question 1: The average production of article ‘A’ in 1^st 12 days of a month is 350 units, and for next 8 days the average production is 150 units. If the average production in whole month of 30 days is 250 units, then find the average production (in units) in last 10 days.

A) 280

B) 300

C) 150

D) 210

E) 140

Question 2: The average age of Ritu, Neetu and Pinki is 30 years, while the ratio of age of Ritu, Neetu and Pinki is 5:7:3, respectively. Find the age of Pinki.

A) 15 years

B) 21 years

C) 24 years

D) 18 years

E) 12 years

Question 3: Average of 12 numbers is 95. Average of first five and last four numbers is 80 and 98, respectively. If sixth, seventh and eighth number are in the ratio of 4:3:1, respectively then find the sixth number.

A) 176

B) 174

C) 172

D) 178

E) None of these

Question 4: Average of 18 numbers is 25 and when two new numbers ‘x’ and ‘y’ are added, average is increased by 5. If x – y = 20 then find the value of y.

A) 95

B) 85

C) 75

D) 65

E) None of these

Question 5: Average of 15 numbers is 54. If the average of first eight numbers is 40 and average of last 4 numbers is 46 and the ratio of rest three numbers is 8:5:4, then find the largest number among rest three numbers.

A) 136

B) 144

C) 152

D) 160

E) None of these

Question 6: Average runs scored by a batsman in first 32 matches is 80. In next 8 matches, he scored runs with an average of ‘x’ such that his average run is increased by 5. Find the value of ‘x’.

A) 85

B) 95

C) 105

D) 115

E) None of these

Question 7: Average of 24 numbers is 75. If average of first 20 numbers is 62 and the remaining four numbers are (x – 12), (x – 8), (x + 8) and (x + 12) respectively, then find the value of x.

A) 120

B) 130

C) 140

D) 150

E) None of these

Question 8: The total number of sweets received by 25 girls in a class is 150. Find the number of boys in the class if the average number of sweets received by each boy is 50% more than that of girls and total sweets distributed is 420.

A) 30

B) 15

C) 20

D) 40

E) 35

Question 9: The average age of 16 females is 25 years while the average age of 20 males is 35 years. Find the approximate average age of each person.

A) 26 years

B) 32 years

C) 28 years

D) 30 years

E) 34 years

Question 10: In a class, the average age of 24 girls is 15 years and the average age of all the boys is 16 years. Find the average age of all the students up to two decimal places if number of boys is 25% more than that of girls.

A) 14.85 years

B) 15.55 years

C) 16.22 years

D) 16.84 years

E) 14.58 years

Solution 1: D)

Required average = {(30 × 250) – (12 × 350) – (8 × 150)}/10 = 210

Hence, option d.

Solution 2: D)

Let, age of Ritu, Neetu and Pinki be 5x years, 7x years and 3x years respectively.

According to question,

(5x + 7x + 3x)/3 = 30

15x = 90

x = 90/15

x = 6

Therefore, age of Pinki = 3 × 6 = 18 years

Hence, option d.

Solution 3: B)

Let sixth, seventh and eighth numbers be 4x, 3x and x, respectively.

Sum of 12 numbers = 12 × 95 = 1140

Sum of sixth, seventh and eighth number = 1140 – 80 × 5 – 98 × 4 = 348

So, 8x = 348

Or, x = 43.5

So, sixth number = 4 × 43.5 = 174

Hence, option b.

Solution 4: D)

Sum of 18 numbers = 18 × 25 = 450

Sum of 20 numbers = 20 × 30 = 600

S, x + y = 600 – 450 = 150 ——(i)

And, x – y = 20 ——-(ii)

From (i) and (ii),

x = 85, y = 65

Hence, option d.

Solution 5: B)

Sum of 15 numbers = 54 × 15 = 810

Sum of the rest three numbers = 810 – 40 × 8 – 46 × 4 = 306

Desired number = 8/17 × 306 = 144

Hence, option b.

Solution 6: C)

Total runs scored in 32 matches = 32 × 80 = 2560

Total runs scored in 40 matches = 40 × 85 = 3400

So, x = (3400 – 2560)/8 = 105

Hence, option c.

Solution 7: C)

Sum of 24 numbers = 24 × 75 = 1800

Sum of 20 numbers = 20 × 62 = 1240

According to question

x – 12 + x – 8 + x + 8 + x + 12 = 1800 – 1240 = 560

Or, 4x = 560

Or, x = 140

Hence, option c.

Solution 8: A)

Number of sweets received by boys = 420 – 150 = 270

Average number of sweets received by each boy = 1.5 × (150/25) = 9

Number of boys = 270/9 = 30

Hence, option a.

Solution 9: D)

Required average age = (16 × 25 + 20 × 35)/36 = 30.55 ~ 30 years

Hence, option d.

Solution 10: B)

Required average = {(24 × 15) + (1.25 × 24 × 16)}/54 = 15.55 years

Hence, option b.

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