Approximation for IBPS RRB Exam- Approximation is an important topic in the quantitative aptitude section of the IBPS RRB exam. It questions a candidate’s ability to quickly and accurately approximate values, which is solving for solving problems efficiently under time constraints. Approximation involves estimating a number or value as close to its actual value as possible, often simplifying complex calculations. This skill is especially useful in exams where quick mental calculations can save candidates time and solve simple questions. These questions usually involve arithmetic operations such as addition, subtraction, multiplication and division. In this article, we provide an overview of the approximation topic, and important questions, and offer strategies for mastering the approximation topics.
Question 1: What approximate value will come in place of the question mark (?) in the following question?(Note: You are not expected to calculate the exact value.)
(56.04% of 550.06 + 19.92 × 18.13) – 121.97 = ?
A) 546
B) 412
C) 326
D) 638
E) 756
Question 2: What approximate value will come in place of the question mark (?) in the following question?(Note: You are not expected to calculate the exact value.)
16.11 × 9.96 – (238.19 – 64.04 × 2.18) = ?
A) 10
B) 50
C) 90
D) 130
E) 180
Question 3: What approximate value will come in place of the question mark (?) in the following question?(Note: You are not expected to calculate the exact value.)
(246.12 + 501.97 + 449.24) ÷ 6.86 = ?
A) 23
B) 84
C) 171
D) 256
E) 312
Question 4: What approximate value will come in place of the question mark (?) in the following question?(Note: You are not expected to calculate the exact value.)
25.05 × 8.99 + 2.043 – 60.03 × 2.99 = ?
A) 78
B) 90
C) 47
D) 29
E) 34
Question 5: What approximate value will come in place of the question mark (?) in the following question?(Note: You are not expected to calculate the exact value.)
?% of 624.98 + 25.04 = 80.02% of 719.98 + 1448.99
A) 320
B) 480
C) 560
D) 120
E) 250
Question 6: What approximate value will come in place of the question mark (?) in the following question?(Note: You are not expected to calculate the exact value.)
(16.02)2 – 19.98% of 200.04 + √288.94 = ?
A) 197
B) 380
C) 233
D) 117
E) 293
Question 7: What approximate value will come in place of the question mark (?) in the following question?(Note: You are not expected to calculate the exact value.)
(660.05) ÷ 120.04% of (55.022/2.24) = (? ÷ 10.02)
A) 240
B) 120
C) 250
D) 200
E) 160
Question 8: What approximate value will come in place of the question mark (?) in the following question?(Note: You are not expected to calculate the exact value.)
√{(26.98)2 × 40.02% of 39.98} + (168.9)1/2 = ?2
A) 16
B) 11
C) 8
D) 21
E) 2
Question 9: What approximate value will come in place of the question mark (?) in the following question?(Note: You are not expected to calculate the exact value.)
(12.01)2 × (1.001)567 – 67.98 = ?2 – 4.98
A) 9
B) 12
C) 15
D) 18
E) 21
Question 10: What approximate value will come in place of the question mark (?) in the following question?(Note: You are not expected to calculate the exact value.)
(80.98)1/2 + 90.02% of 450.02 – ? = 399.98
A) 34
B) 24
C) 14
D) 45
E) 2
Solution 1: A)
(56.04% of 550.06 + 19.92 × 18.13) – 121.97 = ?
(56% of 550 + 20 × 18) – 122 ~ ?
(308 + 360) – 122 ~ ?
546 ~ ?
Hence, option a.
Solution 2: B)
16.11 × 9.96 – (238.19 – 64.04 × 2.18) = ?
16 × 10 – (238 – 64 × 2) ~ ?
160 – (238 – 128) ~ ?
160 – 110 ~ ?
50 ~ ?
Hence, option b.
Solution 3: C)
(246.12 + 501.97 + 449.24) ÷ 6.86 = ?
(246 + 502 + 449) ÷ 7 ~ ?
1197 ÷ 7 ~ ?
171 ~ ?
Hence, option c.
Solution 4: C)
25.05 × 8.99 + 2.043 – 60.03 × 2.99 = ?
25 × 9 + 2 – 60 × 3 ~ ?
225 + 2 – 180 ~ ?
? ~ 47
Hence, option c.
Solution 5: A)
?% of 624.98 + 25.04 = 80.02% of 719.98 + 1448.99
?% of 625 + 25 ~ 80% of 720 + 1449
(?/100) × 625 + 25 ~ (80/100) × 720 + 1449
(?/100) × 625 ~ 576 + 1449 – 25
? ~ {(2000 × 100)/625}
? ~ 320
Hence, option a.
Solution 6: C)
(16.02)2 – 19.98% of 200.04 + √288.94 = ?
(16)2 – 20% of 200 + √289 ~ ?
256 – (20/100) × 200 + 17 ~ ?
256 – 40 + 17 ~ ?
? ~ 233
Hence, option c.
Solution 7: D)
(660.05) ÷ 120.04% of (55.022/2.24) = (? ÷ 10.02)
660 ÷ {(120/100) × (55/2)} ~ (?/10)
(660 ÷ 33) × 10 ~ ?
20 × 10 ~ ?
? ~ 200
Hence, option d.
Solution 8: B)
√{(26.98)2 × 40.02% of 39.98} + (168.9)1/2 = ?2
√{(27)2 × 40% of 40} + (169)1/2 ~ ?2
√{(27)2 × 16} + 13 ~ ?2
27 × 4 + 13 ~ ?2
121 ~ ?2
? ~ ±11
Hence, option b.
Solution 9: A)
(12.01)2 × (1.001)567 – 67.98 = ?2 – 4.98
(12)2 × (1)567 – (68) ~ ?2 – 5
144 – 68 + 5 ~ ?2
81 ~ ?2
? ~ ±9
Hence, option a.
Solution 10: C)
(80.98)1/2 + 90.02% of 450.02 – ? = 399.98
(81)1/2 + 90% of 450 – ? ~ 400
9 + 405 – 400 ~ ?
? ~ 14
Hence, option c.
Approximation involves finding a value that is close enough to the correct answer for practical purposes. It helps in quickly estimating answers to save time.
Approximation helps to solve problems faster by avoiding lengthy calculations, which is
key for managing time during competitive exams.
Questions can involve estimating values in arithmetic operations, solving equations, simplifying fractions, and dealing with percentages and ratios.
Simplify the fraction to its nearest simple fraction or decimal. For example, approximate 22/7 as 3.14 or 23/7 as approximately 3.3.
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